Given a set of elements N = {1, 2, ..., n} and two arbitrary subsets AN and BN, how many of the n! permutations from N to N satisfy min((A)) = min((B)), where min(S) is the smallest integer in the set of integers S, and (S) is the set of integers obtained by applying permutation to each element of S?a)(n - -A B-) -A- -B-b)(-A-2+-B-2)n2c)n! -AB- / -AB-d)-AB-2nC-ABCorrect answer is option 'C'. Can you explain this answer? - EduRev Computer Science Engineering (CSE) Question

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Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > Given a set of elements N = {1, 2, ..., n} an...

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a)
(n - |A ∪ B|) |A| |B|
b)
(|A|²+|B|²)n²
c)
n! |A∩B| / |A∪B|
d)
|A∩B|²nC|A∪B

Correct answer is option 'C'. Can you explain this answer?

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Given a set of elements N = {1, 2, ..., n} and two arbitrary subsets A...

First let us understand what question is asking. So π is a function from N to N, which just permutes the elements of N, so there will be n! such permutations. Now given a particular π i.e. given a particular permutation scheme, we have to find number of permutations out of these n! permuations in which minimum elements of A and B after applying π to them are same. So for example, if N = {1,2,3}, π is {2,3,1}, and if A is {1,3}, then π(A) = {2,1}. Now number of elements in A ∪ B is |A ∪ B|. We can choose permutations for A ∪ B in nC|A∪B| ways. Note that here we are just choosing elements for permutation, and not actually permuting. Let this chosen set be P. Now once we have chosen numbers for permutations, we have to select mapping from each element of A ∪ B to some element of P. So first of all, to achieve required condition specified in question, we have to map minimum number in P to any of the number in A ∩ B, so that min(π(A)) = min(π(B)). We can do this in |A∩B| ways, since we can choose any element of |A∩B| to be mapped to minimum number in P. Now we come to permutation. We can permute numbers in P in |A∪B-1|! ways, since one number (minimum) is already fixed. Moreover, we can also permute remaining n - |A∪B-1| in (n - |A∪B-1|)! ways, so total no. of ways = nC|A∪B|∗|A∩B|∗|A∪B−1|!∗(n−|A∪B−1|)!=n!|A∩B||A∪B| So option (C) is correct. Note: Some answer keys on web have shown answer as option (D), which is clearly incorrect. Suppose |A ∪ B| = 3, and |A ∩ B| = 1, and n = 4, then option (D) evaluates to 14=0.25, which doesn't make sense.

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Given a set of elements N = {1, 2, ..., n} and two arbitrary subsets A⊆N and B⊆N, how many of the n! permutations π from N to N satisfy min(π(A)) = min(π(B)), where min(S) is the smallest integer in the set of integers S, and π(S) is the set of integers obtained by applying permutation π to each element of S?a)(n - |A ∪ B|) |A| |B|b)(|A|2+|B|2)n2c)n! |A∩B| / |A∪B|d)|A∩B|2nC|A∪BCorrect answer is option 'C'. Can you explain this answer?

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Given a set of elements N = {1, 2, ..., n} and two arbitrary subsets A⊆N and B⊆N, how many of the n! permutations π from N to N satisfy min(π(A)) = min(π(B)), where min(S) is the smallest integer in the set of integers S, and π(S) is the set of integers obtained by applying permutation π to each element of S?a)(n - |A ∪ B|) |A| |B|b)(|A|2+|B|2)n2c)n! |A∩B| / |A∪B|d)|A∩B|2nC|A∪BCorrect answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Given a set of elements N = {1, 2, ..., n} and two arbitrary subsets A⊆N and B⊆N, how many of the n! permutations π from N to N satisfy min(π(A)) = min(π(B)), where min(S) is the smallest integer in the set of integers S, and π(S) is the set of integers obtained by applying permutation π to each element of S?a)(n - |A ∪ B|) |A| |B|b)(|A|2+|B|2)n2c)n! |A∩B| / |A∪B|d)|A∩B|2nC|A∪BCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given a set of elements N = {1, 2, ..., n} and two arbitrary subsets A⊆N and B⊆N, how many of the n! permutations π from N to N satisfy min(π(A)) = min(π(B)), where min(S) is the smallest integer in the set of integers S, and π(S) is the set of integers obtained by applying permutation π to each element of S?a)(n - |A ∪ B|) |A| |B|b)(|A|2+|B|2)n2c)n! |A∩B| / |A∪B|d)|A∩B|2nC|A∪BCorrect answer is option 'C'. Can you explain this answer?.

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