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Minimum interplanar spacing required for Bragg’s diffraction is:
- a)λ/4
- b)λ/2
- c)λ
- d)2λ
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Minimum interplanar spacing required for Bragg’s diffraction is:...
Explanation: Maximum value of incident angle can be 90° for which sine is 1. Hence d = λ/2 ( nλ = 2.d.sinθ)
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Minimum interplanar spacing required for Bragg’s diffraction is:...
The minimum interplanar spacing required for Bragg diffraction is given by the Bragg's law:
nλ = 2d sinθ
where n is the order of diffraction, λ is the wavelength of the incident radiation, d is the interplanar spacing, and θ is the angle of diffraction.
To determine the minimum interplanar spacing required, we can rearrange the equation as:
d = nλ / (2sinθ)
Since we want to find the minimum interplanar spacing, we can consider the first-order diffraction (n = 1) and the maximum angle of diffraction (θ = 90 degrees). In this case, the equation becomes:
d = λ / 2
Therefore, the minimum interplanar spacing required for Bragg diffraction is equal to half the wavelength of the incident radiation.
nλ = 2d sinθ
where n is the order of diffraction, λ is the wavelength of the incident radiation, d is the interplanar spacing, and θ is the angle of diffraction.
To determine the minimum interplanar spacing required, we can rearrange the equation as:
d = nλ / (2sinθ)
Since we want to find the minimum interplanar spacing, we can consider the first-order diffraction (n = 1) and the maximum angle of diffraction (θ = 90 degrees). In this case, the equation becomes:
d = λ / 2
Therefore, the minimum interplanar spacing required for Bragg diffraction is equal to half the wavelength of the incident radiation.
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Minimum interplanar spacing required for Bragg’s diffraction is:a)λ/4b)λ/2c)λd)2λCorrect answer is option 'B'. Can you explain this answer?
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