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In a cyclic process, the work done by the system is 20 kJ, -30 kJ, -5 kJ and 10 kJ. What is the net heat (kJ) for the cyclic process?
- a)-5
- b)0
- c)5
- d)10
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In a cyclic process, the work done by the system is 20 kJ, -30 kJ, -5 ...
dQ = dW + ΔU (As per first law)
For the cyclic process,
ΔU = 0
∴∫dW=∫dQ∴∫dW=∫dQ
∴ W = 20 - 30 - 5 + 10
= -5 kJ
Most Upvoted Answer
In a cyclic process, the work done by the system is 20 kJ, -30 kJ, -5 ...
Given information:
Work done by the system:
- First process: 20 kJ (positive work, work done on the system)
- Second process: -30 kJ (negative work, work done by the system)
- Third process: -5 kJ (negative work, work done by the system)
- Fourth process: 10 kJ (positive work, work done on the system)
To find: Net heat for the cyclic process
Formula:
According to the First Law of Thermodynamics, the net heat (Q) for a cyclic process is equal to the net work (W) done by the system.
Calculation:
To calculate the net heat, we need to sum up the work done by the system.
Net work done = (20 kJ) + (-30 kJ) + (-5 kJ) + (10 kJ)
= -5 kJ
Since the work done is negative, the net heat will also be negative.
Therefore, the correct option is (a) -5 kJ.
Explanation:
In a cyclic process, the system undergoes a series of changes and returns to its initial state. The work done by the system during this process can be positive or negative, depending on whether work is done on or by the system. The net heat for a cyclic process is equal to the net work done by the system, according to the First Law of Thermodynamics.
In this case, the work done by the system is given as 20 kJ, -30 kJ, -5 kJ, and 10 kJ for the four processes in the cycle. Summing up these values, we get a net work done of -5 kJ. Since the work done is negative, the net heat for the cyclic process will also be negative. Hence, the correct option is -5 kJ.
Work done by the system:
- First process: 20 kJ (positive work, work done on the system)
- Second process: -30 kJ (negative work, work done by the system)
- Third process: -5 kJ (negative work, work done by the system)
- Fourth process: 10 kJ (positive work, work done on the system)
To find: Net heat for the cyclic process
Formula:
According to the First Law of Thermodynamics, the net heat (Q) for a cyclic process is equal to the net work (W) done by the system.
Calculation:
To calculate the net heat, we need to sum up the work done by the system.
Net work done = (20 kJ) + (-30 kJ) + (-5 kJ) + (10 kJ)
= -5 kJ
Since the work done is negative, the net heat will also be negative.
Therefore, the correct option is (a) -5 kJ.
Explanation:
In a cyclic process, the system undergoes a series of changes and returns to its initial state. The work done by the system during this process can be positive or negative, depending on whether work is done on or by the system. The net heat for a cyclic process is equal to the net work done by the system, according to the First Law of Thermodynamics.
In this case, the work done by the system is given as 20 kJ, -30 kJ, -5 kJ, and 10 kJ for the four processes in the cycle. Summing up these values, we get a net work done of -5 kJ. Since the work done is negative, the net heat for the cyclic process will also be negative. Hence, the correct option is -5 kJ.
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