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0.2 ml of a microbial culture was diluted by adding 9.8ml of buffer to 10 ml. 0.1ml of this was further diluted by adding 9.9 ml of buffer to 10 ml. Plating 0.5 ml from 2nd tube yields 80 colonies. Cell density in original culture was ____________ x 104 cells. (Round off to one decimal place)
Correct answer is between '1.4,1.7'. Can you explain this answer?
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Calculation of Cell Density in Original Culture
Dilution of the Culture
- 0.2 ml of microbial culture is diluted by adding 9.8 ml of buffer to make a total volume of 10 ml.
- This gives a dilution factor of (10/0.2) = 50.
- Thus, the cell density in the first tube is 50 times less than the original culture.
Further Dilution of the Culture
- 0.1 ml of the first tube is diluted by adding 9.9 ml of buffer to make a total volume of 10 ml.
- This gives a dilution factor of (10/0.1) = 100.
- Thus, the total dilution factor is (50 x 100) = 5000.
Calculation of Cell Density
- Plating 0.5 ml from the second tube yields 80 colonies.
- The number of colonies on the plate represents the number of viable cells in the plated volume.
- Therefore, the number of viable cells in 1 ml of the second tube is (80/0.5) = 160.
- As the total dilution factor is 5000, the number of viable cells in 1 ml of the original culture is (160 x 5000) = 800000.
- This is equivalent to (800000/10000) = 80 x 10^4 cells/ml.
- Therefore, the cell density in the original culture is between 1.4 x 10^4 cells/ml and 1.7 x 10^4 cells/ml.
Answer: The cell density in the original culture is between 1.4 x 10^4 cells/ml and 1.7 x 10^4 cells/ml.
Dilution of the Culture
- 0.2 ml of microbial culture is diluted by adding 9.8 ml of buffer to make a total volume of 10 ml.
- This gives a dilution factor of (10/0.2) = 50.
- Thus, the cell density in the first tube is 50 times less than the original culture.
Further Dilution of the Culture
- 0.1 ml of the first tube is diluted by adding 9.9 ml of buffer to make a total volume of 10 ml.
- This gives a dilution factor of (10/0.1) = 100.
- Thus, the total dilution factor is (50 x 100) = 5000.
Calculation of Cell Density
- Plating 0.5 ml from the second tube yields 80 colonies.
- The number of colonies on the plate represents the number of viable cells in the plated volume.
- Therefore, the number of viable cells in 1 ml of the second tube is (80/0.5) = 160.
- As the total dilution factor is 5000, the number of viable cells in 1 ml of the original culture is (160 x 5000) = 800000.
- This is equivalent to (800000/10000) = 80 x 10^4 cells/ml.
- Therefore, the cell density in the original culture is between 1.4 x 10^4 cells/ml and 1.7 x 10^4 cells/ml.
Answer: The cell density in the original culture is between 1.4 x 10^4 cells/ml and 1.7 x 10^4 cells/ml.
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0.2 ml of a microbial culture was diluted by adding 9.8ml of buffer to 10 ml. 0.1ml of this was further diluted by adding 9.9 ml of buffer to 10 ml. Plating 0.5 ml from 2nd tube yields 80 colonies. Cell density in original culture was ____________ x 104 cells. (Round off to one decimal place)Correct answer is between '1.4,1.7'. Can you explain this answer?
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0.2 ml of a microbial culture was diluted by adding 9.8ml of buffer to 10 ml. 0.1ml of this was further diluted by adding 9.9 ml of buffer to 10 ml. Plating 0.5 ml from 2nd tube yields 80 colonies. Cell density in original culture was ____________ x 104 cells. (Round off to one decimal place)Correct answer is between '1.4,1.7'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about 0.2 ml of a microbial culture was diluted by adding 9.8ml of buffer to 10 ml. 0.1ml of this was further diluted by adding 9.9 ml of buffer to 10 ml. Plating 0.5 ml from 2nd tube yields 80 colonies. Cell density in original culture was ____________ x 104 cells. (Round off to one decimal place)Correct answer is between '1.4,1.7'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.2 ml of a microbial culture was diluted by adding 9.8ml of buffer to 10 ml. 0.1ml of this was further diluted by adding 9.9 ml of buffer to 10 ml. Plating 0.5 ml from 2nd tube yields 80 colonies. Cell density in original culture was ____________ x 104 cells. (Round off to one decimal place)Correct answer is between '1.4,1.7'. Can you explain this answer?.
0.2 ml of a microbial culture was diluted by adding 9.8ml of buffer to 10 ml. 0.1ml of this was further diluted by adding 9.9 ml of buffer to 10 ml. Plating 0.5 ml from 2nd tube yields 80 colonies. Cell density in original culture was ____________ x 104 cells. (Round off to one decimal place)Correct answer is between '1.4,1.7'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about 0.2 ml of a microbial culture was diluted by adding 9.8ml of buffer to 10 ml. 0.1ml of this was further diluted by adding 9.9 ml of buffer to 10 ml. Plating 0.5 ml from 2nd tube yields 80 colonies. Cell density in original culture was ____________ x 104 cells. (Round off to one decimal place)Correct answer is between '1.4,1.7'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.2 ml of a microbial culture was diluted by adding 9.8ml of buffer to 10 ml. 0.1ml of this was further diluted by adding 9.9 ml of buffer to 10 ml. Plating 0.5 ml from 2nd tube yields 80 colonies. Cell density in original culture was ____________ x 104 cells. (Round off to one decimal place)Correct answer is between '1.4,1.7'. Can you explain this answer?.
Solutions for 0.2 ml of a microbial culture was diluted by adding 9.8ml of buffer to 10 ml. 0.1ml of this was further diluted by adding 9.9 ml of buffer to 10 ml. Plating 0.5 ml from 2nd tube yields 80 colonies. Cell density in original culture was ____________ x 104 cells. (Round off to one decimal place)Correct answer is between '1.4,1.7'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM.
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