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A microorganism has a specific growth rate of 2.8 h–1, its doubling time will be _______ minutes. (Round off to two deimal places).
Correct answer is between '14.82,14.87'. Can you explain this answer?
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A microorganism has a specific growth rate of 2.8 h–1, its doubl...
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A microorganism has a specific growth rate of 2.8 h–1, its doubl...
To calculate the doubling time of the microorganism, we can use the formula:
Doubling Time (h) = ln(2) / Growth Rate (h)
In this case, the growth rate is given as 2.8 h.
Doubling Time = ln(2) / 2.8
Using a calculator or math software, we can find the doubling time:
Doubling Time ≈ 0.693 / 2.8 ≈ 0.2475 hours
Therefore, the doubling time of the microorganism is approximately 0.2475 hours.
Doubling Time (h) = ln(2) / Growth Rate (h)
In this case, the growth rate is given as 2.8 h.
Doubling Time = ln(2) / 2.8
Using a calculator or math software, we can find the doubling time:
Doubling Time ≈ 0.693 / 2.8 ≈ 0.2475 hours
Therefore, the doubling time of the microorganism is approximately 0.2475 hours.
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A microorganism has a specific growth rate of 2.8 h–1, its doubling time will be _______ minutes. (Round off to two deimal places).Correct answer is between '14.82,14.87'. Can you explain this answer?
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