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In a Room 2 fans consuming 0.18 kW and three 100 W bulbs are used at time. Air at a rate of 80 kg/hr ent er the room with an enthalpy of 84 kJ/kg and leaves at 59 kJ/kg. T he rate at which heat is to be removed by the room cooler, so as to maintain steady state is __________kW
Correct answer is between '1.15,1.30'. Can you explain this answer?
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Solution:
Given data:
Number of fans = 2
Power consumed by each fan = 0.18 kW
Total Power consumed by fans = 2 × 0.18 kW = 0.36 kW
Number of bulbs = 3
Power consumed by each bulb = 100 W
Total power consumed by bulbs = 3 × 100 W = 300 W = 0.3 kW
Rate of air entering the room = 80 kg/hr
Enthalpy of air entering the room = 84 kJ/kg
Enthalpy of air leaving the room = 59 kJ/kg
To maintain steady state, the rate at which heat is to be removed by the room cooler is equal to the rate at which heat is generated inside the room.
Heat generated inside the room can be calculated as:
Heat generated = Heat generated by fans + Heat generated by bulbs + Heat generated by the air entering the room
Heat generated by fans = Power consumed by fans × Time
= 0.36 kW × 1 hr
= 0.36 kWh
Heat generated by bulbs = Power consumed by bulbs × Time
= 0.3 kW × 1 hr
= 0.3 kWh
Heat generated by the air entering the room can be calculated using the formula:
Heat generated = Mass flow rate × Enthalpy difference
Mass flow rate of air = 80 kg/hr
Enthalpy difference = Enthalpy of air entering the room - Enthalpy of air leaving the room
= 84 kJ/kg - 59 kJ/kg
= 25 kJ/kg
Heat generated by the air entering the room = Mass flow rate × Enthalpy difference
= 80 kg/hr × 25 kJ/kg
= 2000 kJ/hr
= 0.56 kWh
Total heat generated inside the room = Heat generated by fans + Heat generated by bulbs + Heat generated by the air entering the room
= 0.36 kWh + 0.3 kWh + 0.56 kWh
= 1.22 kWh
To maintain steady state, the rate at which heat is to be removed by the room cooler = 1.22 kWh/hr = 1.22 kW
Therefore, the rate at which heat is to be removed by the room cooler, so as to maintain steady state is between 1.15 kW and 1.30 kW.
Given data:
Number of fans = 2
Power consumed by each fan = 0.18 kW
Total Power consumed by fans = 2 × 0.18 kW = 0.36 kW
Number of bulbs = 3
Power consumed by each bulb = 100 W
Total power consumed by bulbs = 3 × 100 W = 300 W = 0.3 kW
Rate of air entering the room = 80 kg/hr
Enthalpy of air entering the room = 84 kJ/kg
Enthalpy of air leaving the room = 59 kJ/kg
To maintain steady state, the rate at which heat is to be removed by the room cooler is equal to the rate at which heat is generated inside the room.
Heat generated inside the room can be calculated as:
Heat generated = Heat generated by fans + Heat generated by bulbs + Heat generated by the air entering the room
Heat generated by fans = Power consumed by fans × Time
= 0.36 kW × 1 hr
= 0.36 kWh
Heat generated by bulbs = Power consumed by bulbs × Time
= 0.3 kW × 1 hr
= 0.3 kWh
Heat generated by the air entering the room can be calculated using the formula:
Heat generated = Mass flow rate × Enthalpy difference
Mass flow rate of air = 80 kg/hr
Enthalpy difference = Enthalpy of air entering the room - Enthalpy of air leaving the room
= 84 kJ/kg - 59 kJ/kg
= 25 kJ/kg
Heat generated by the air entering the room = Mass flow rate × Enthalpy difference
= 80 kg/hr × 25 kJ/kg
= 2000 kJ/hr
= 0.56 kWh
Total heat generated inside the room = Heat generated by fans + Heat generated by bulbs + Heat generated by the air entering the room
= 0.36 kWh + 0.3 kWh + 0.56 kWh
= 1.22 kWh
To maintain steady state, the rate at which heat is to be removed by the room cooler = 1.22 kWh/hr = 1.22 kW
Therefore, the rate at which heat is to be removed by the room cooler, so as to maintain steady state is between 1.15 kW and 1.30 kW.
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In a Room 2 fans consuming 0.18 kW and three 100 W bulbs are used at time. Air at a rate of 80 kg/hr ent er the room with an enthalpy of 84 kJ/kg and leaves at 59 kJ/kg. T he rate at which heat is to be removed by the room cooler, so as to maintain steady state is __________kWCorrect answer is between '1.15,1.30'. Can you explain this answer?
Question Description
In a Room 2 fans consuming 0.18 kW and three 100 W bulbs are used at time. Air at a rate of 80 kg/hr ent er the room with an enthalpy of 84 kJ/kg and leaves at 59 kJ/kg. T he rate at which heat is to be removed by the room cooler, so as to maintain steady state is __________kWCorrect answer is between '1.15,1.30'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a Room 2 fans consuming 0.18 kW and three 100 W bulbs are used at time. Air at a rate of 80 kg/hr ent er the room with an enthalpy of 84 kJ/kg and leaves at 59 kJ/kg. T he rate at which heat is to be removed by the room cooler, so as to maintain steady state is __________kWCorrect answer is between '1.15,1.30'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a Room 2 fans consuming 0.18 kW and three 100 W bulbs are used at time. Air at a rate of 80 kg/hr ent er the room with an enthalpy of 84 kJ/kg and leaves at 59 kJ/kg. T he rate at which heat is to be removed by the room cooler, so as to maintain steady state is __________kWCorrect answer is between '1.15,1.30'. Can you explain this answer?.
In a Room 2 fans consuming 0.18 kW and three 100 W bulbs are used at time. Air at a rate of 80 kg/hr ent er the room with an enthalpy of 84 kJ/kg and leaves at 59 kJ/kg. T he rate at which heat is to be removed by the room cooler, so as to maintain steady state is __________kWCorrect answer is between '1.15,1.30'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a Room 2 fans consuming 0.18 kW and three 100 W bulbs are used at time. Air at a rate of 80 kg/hr ent er the room with an enthalpy of 84 kJ/kg and leaves at 59 kJ/kg. T he rate at which heat is to be removed by the room cooler, so as to maintain steady state is __________kWCorrect answer is between '1.15,1.30'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a Room 2 fans consuming 0.18 kW and three 100 W bulbs are used at time. Air at a rate of 80 kg/hr ent er the room with an enthalpy of 84 kJ/kg and leaves at 59 kJ/kg. T he rate at which heat is to be removed by the room cooler, so as to maintain steady state is __________kWCorrect answer is between '1.15,1.30'. Can you explain this answer?.
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