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Find the magnetic force when a charge 3.5C with flux density of 4 units is having a velocity of 2m/s.
- a)14
- b)28
- c)7
- d)32
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Find the magnetic force when a charge 3.5C with flux density of 4 unit...
Answer: b
Explanation: The magnetic force is given by F = q(v x B), where q = 3.5C, v = 2m/s and B = 4 units. Thus we get F = 3.5(2 x 4) = 28 units.
Explanation: The magnetic force is given by F = q(v x B), where q = 3.5C, v = 2m/s and B = 4 units. Thus we get F = 3.5(2 x 4) = 28 units.
Most Upvoted Answer
Find the magnetic force when a charge 3.5C with flux density of 4 unit...
Magnetic Force on a Moving Charge
The magnetic force on a moving charge can be calculated using the formula:
F = q * v * B * sin(theta)
Where:
F is the magnetic force
q is the charge
v is the velocity of the charge
B is the magnetic flux density
theta is the angle between the velocity and the magnetic field
In this case, we are given:
q = 3.5C (charge)
v = 2m/s (velocity)
B = 4 units (magnetic flux density)
Solving the Problem
First, let's calculate the angle between the velocity and the magnetic field. Since the question does not provide any information about the angle, we will assume it to be 90 degrees (perpendicular).
theta = 90 degrees
Now, let's substitute the given values into the formula:
F = (3.5C) * (2m/s) * (4 units) * sin(90 degrees)
Since sin(90 degrees) = 1, the equation simplifies to:
F = (3.5C) * (2m/s) * (4 units) * 1
F = 28 N
Therefore, the magnetic force on the charge is 28 N.
Answer: Option B (28)
The magnetic force on a moving charge can be calculated using the formula:
F = q * v * B * sin(theta)
Where:
F is the magnetic force
q is the charge
v is the velocity of the charge
B is the magnetic flux density
theta is the angle between the velocity and the magnetic field
In this case, we are given:
q = 3.5C (charge)
v = 2m/s (velocity)
B = 4 units (magnetic flux density)
Solving the Problem
First, let's calculate the angle between the velocity and the magnetic field. Since the question does not provide any information about the angle, we will assume it to be 90 degrees (perpendicular).
theta = 90 degrees
Now, let's substitute the given values into the formula:
F = (3.5C) * (2m/s) * (4 units) * sin(90 degrees)
Since sin(90 degrees) = 1, the equation simplifies to:
F = (3.5C) * (2m/s) * (4 units) * 1
F = 28 N
Therefore, the magnetic force on the charge is 28 N.
Answer: Option B (28)
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