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The per-unit impedance of a circuit element of 0.15. If the base kV and base MVA are halved, then the new value of the per-unit impedance of the circuit element will be
  • a)
    0.075
  • b)
    0.15
  • c)
    0.30
  • d)
    0.60
Correct answer is option 'C'. Can you explain this answer?
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The per-unit impedance of a circuit element of 0.15. If the base kV an...
Given: per-unit impedance of a circuit element = 0.15

When the base kV and base MVA are halved,

New base kV = 0.5 * old base kV
New base MVA = 0.5 * old base MVA

Therefore, new per-unit impedance = old per-unit impedance * (old base kV / new base kV) * (new base MVA / old base MVA)

Substituting the values, we get:

New per-unit impedance = 0.15 * (1 / 0.5) * (0.5 / 1) = 0.30

Hence, the new value of the per-unit impedance of the circuit element will be 0.30, which is option C.
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The per-unit impedance of a circuit element of 0.15. If the base kV and base MVA are halved, then the new value of the per-unit impedance of the circuit element will bea)0.075b)0.15c)0.30d)0.60Correct answer is option 'C'. Can you explain this answer?
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