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In the Hopkinson’s test on two DC machines. Machine A has field current of 1.4A and B has field current of 1.3A. Which machine acts as generator?
  • a)
    B
  • b)
    A
  • c)
    A,B
  • d)
    None of the mentioned
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In the Hopkinson’s test on two DC machines. Machine A has field ...
Ea/Eb = 1.4/1.3
Ea= 1.077 Eb > Eb
So, the machine will act as generator.
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Most Upvoted Answer
In the Hopkinson’s test on two DC machines. Machine A has field ...
The Hopkinson is a type of bridge circuit used in electronics and electrical engineering. It was invented by the British engineer John Hopkinson in the late 19th century. The Hopkinson bridge is used to measure the impedance of a circuit or component.

The Hopkinson bridge consists of four arms, with three of them containing known resistors and the fourth arm containing the unknown impedance. The resistor values are carefully chosen to create a balanced bridge circuit, where the voltages across opposite arms cancel each other out.

By measuring the voltage across the fourth arm, the impedance of the unknown component can be calculated. The Hopkinson bridge is commonly used in laboratories and research settings to measure the characteristics of electronic components and circuits.

The Hopkinson bridge has been widely used in various applications, including telecommunications, power systems, and audio equipment. It is a versatile circuit that allows engineers to accurately measure the impedance of different components.

Overall, the Hopkinson bridge is an important tool in electrical engineering, providing a reliable method for measuring impedance and understanding the behavior of electronic circuits and components.
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In the Hopkinson’s test on two DC machines. Machine A has field current of 1.4A and B has field current of 1.3A. Which machine acts as generator?a)Bb)Ac)A,Bd)None of the mentionedCorrect answer is option 'B'. Can you explain this answer?
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