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To 5.85 g of NaCl, one kg of water is added to prepare a solution. What is the strength of NaCl in this colution ? (Molecular weight of NaCl = 58.5)
  • a)
    0.1 Normal
  • b)
    0.1 Molal
  • c)
    0.1 Molar
  • d)
    0.1 Formal
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
To 5.85 g of NaCl, one kg of water is added to prepare a solution. Wha...
5.85g NaCl = 0.1 mol. As it is present in 1 kg of water, strength = 0.1 molal.
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Most Upvoted Answer
To 5.85 g of NaCl, one kg of water is added to prepare a solution. Wha...
Given:
Mass of NaCl = 5.85 g
Mass of water = 1 kg = 1000 g
Molecular weight of NaCl = 58.5 g/mol

To find:
Strength of NaCl in the solution

Solution:

1. Calculation of moles of NaCl:
Moles of NaCl = Mass of NaCl / Molecular weight of NaCl
= 5.85 g / 58.5 g/mol
= 0.1 mol

2. Calculation of molality of the solution:
Molality (m) = Moles of solute / Mass of solvent (in kg)
= 0.1 mol / 1 kg
= 0.1 mol/kg

3. Comparison with options:
a) 0.1 Normal: Normality is defined as the number of gram equivalents of solute present in one litre of solution. As NaCl is a neutral molecule, its gram equivalent weight is equal to its molecular weight. Therefore, 0.1 N solution of NaCl would contain 5.85 g of NaCl in one litre of solution. Hence, this option is not correct as the given solution has a greater volume than one litre.

b) 0.1 Molal: Molality is defined as the number of moles of solute present in one kg of solvent. As calculated above, the given solution has a molality of 0.1 mol/kg. Hence, this option is correct.

c) 0.1 Molar: Molarity is defined as the number of moles of solute present in one litre of solution. To convert molality to molarity, we need to know the density of the solution. As it is not given, we cannot calculate the molarity of the solution.

d) 0.1 Formal: Formality is defined as the number of gram equivalents of solute present in one litre of solution. As NaCl is a neutral molecule, its gram equivalent weight is equal to its molecular weight. Therefore, 0.1 F solution of NaCl would contain 5.85 g of NaCl in one litre of solution. Hence, this option is not correct as the given solution has a greater volume than one litre.

Therefore, the correct option is (b) 0.1 Molal.
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Chemical reactions involve interaction of atoms and molecules. A large number of atoms/molecules (approximately 6.023 × 1023) are present in a few grams of any chemical compound varying with their atomic/molecular masses. To handle such large numbers conveniently, the mole concept was introduced.This concept has implications in diverse areas such as analytical chemistry, biochemistry, electrochemistry and radiochemistry. The following example illustrates a typical case, involving chemical/electrochemical reaction, which requires a clear understanding of the mole concept. A 4.0 molar aqueous solution NaCl is prepared and 500 mL of this solution is electrolysed. This leads to the evolution of chlorine gas at one of the electrodes (atomic mass: Na = 23, Hg = 200; 1 Faraday = 96,500 coulombs)If the cathode is a Hg electrode, the maximum weight (g) of amalgam formed from this solution is Correct answer is '446'. Can you explain this answer?

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To 5.85 g of NaCl, one kg of water is added to prepare a solution. What is the strength of NaCl in this colution ? (Molecular weight of NaCl = 58.5)a) 0.1 Normal b) 0.1 Molal c) 0.1 Molar d) 0.1 Formal Correct answer is option 'B'. Can you explain this answer?
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