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A cylindrical elastic body subjected to pure torsion about its axis develops
- a)tensile stress in a direction 45º to the axis
- b)no tensile or compressive stress
- c)maximum shear stress along the axis of the shaft
- d)Maximum shear stress at 45º to the axis
Correct answer is option 'A'. Can you explain this answer?
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Explanation:
When a cylindrical elastic body is subjected to pure torsion about its axis, the stress distribution in the body is not uniform. The stress varies across the cross-section of the body.
Shear Stress:
During torsion, shear stress is developed in the body. Shear stress is the stress that acts parallel to the cross-section of the body. It is responsible for the deformation and failure of the body under torsional loading.
Tensile and Compressive Stress:
Tensile and compressive stresses are normal stresses that act perpendicular to the cross-section of the body. In the case of pure torsion, there is no axial force acting on the body, which means there is no tensile or compressive stress developed along the axis of the body.
Maximum Shear Stress:
The maximum shear stress is developed on the surface of the body. It occurs at a 45-degree angle to the axis of the body. This maximum shear stress is given by the equation:
τ_max = (T * r) / J
Where:
τ_max = Maximum shear stress
T = Torque applied
r = Radius of the body
J = Polar moment of inertia
Answer:
In the given question, the body is subjected to pure torsion. Since there is no axial force, there is no tensile or compressive stress developed along the axis of the body. However, the maximum shear stress is developed on the surface of the body, which occurs at a 45-degree angle to the axis. Therefore, the correct answer is option 'A' - tensile stress in a direction 45 to the axis.
When a cylindrical elastic body is subjected to pure torsion about its axis, the stress distribution in the body is not uniform. The stress varies across the cross-section of the body.
Shear Stress:
During torsion, shear stress is developed in the body. Shear stress is the stress that acts parallel to the cross-section of the body. It is responsible for the deformation and failure of the body under torsional loading.
Tensile and Compressive Stress:
Tensile and compressive stresses are normal stresses that act perpendicular to the cross-section of the body. In the case of pure torsion, there is no axial force acting on the body, which means there is no tensile or compressive stress developed along the axis of the body.
Maximum Shear Stress:
The maximum shear stress is developed on the surface of the body. It occurs at a 45-degree angle to the axis of the body. This maximum shear stress is given by the equation:
τ_max = (T * r) / J
Where:
τ_max = Maximum shear stress
T = Torque applied
r = Radius of the body
J = Polar moment of inertia
Answer:
In the given question, the body is subjected to pure torsion. Since there is no axial force, there is no tensile or compressive stress developed along the axis of the body. However, the maximum shear stress is developed on the surface of the body, which occurs at a 45-degree angle to the axis. Therefore, the correct answer is option 'A' - tensile stress in a direction 45 to the axis.
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A cylindrical elastic body subjected to pure torsion about its axis developsa)tensile stress in a direction 45º to the axisb)no tensile or compressive stressc)maximum shear stress along the axis of the shaftd)Maximum shear stress at 45º to the axisCorrect answer is option 'A'. Can you explain this answer?
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