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Find the magnetic field intensity due to an infinite sheet of current 5A and charge density of 12j units in the positive y direction and the z component is above the sheet.
  • a)
    -6
  • b)
    12k
  • c)
    60
  • d)
    6
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Find the magnetic field intensity due to an infinite sheet of current ...
Answer: d
Explanation: The magnetic field intensity when the normal component is above the sheet is Hx = 0.5 K, where K = 12. Thus we get H = 0.5 x 12 = 6 units.
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Most Upvoted Answer
Find the magnetic field intensity due to an infinite sheet of current ...
To find the magnetic field intensity due to an infinite sheet of current, we can use Ampere's Law. Ampere's Law states that the line integral of the magnetic field around a closed loop is equal to the product of the current enclosed by the loop and the permeability of free space (μ0).

Given:
Current density (J) = 5 A
Charge density (ρ) = 12 j units
z-component of the field above the sheet

Let's calculate the magnetic field intensity step by step:

1. Determine the current enclosed by a closed loop above the sheet:
Since the sheet is infinite, the entire current is enclosed by any closed loop above the sheet. Therefore, the current enclosed is equal to the total current (J) = 5 A.

2. Determine the direction of the magnetic field:
The magnetic field due to an infinite sheet of current is perpendicular to the sheet and follows the right-hand rule. In this case, the magnetic field will be in the negative x-direction.

3. Determine the shape of the closed loop:
Since the magnetic field is in the negative x-direction, we can choose a rectangular loop with sides parallel to the y and z axes. The loop will have a height (h) in the y-direction and a width (w) in the z-direction.

4. Calculate the line integral of the magnetic field around the closed loop:
The line integral of the magnetic field along the sides parallel to the y-axis will be zero since the magnetic field is perpendicular to these sides. Therefore, we only need to calculate the line integral along the sides parallel to the z-axis.

Using Ampere's Law, the line integral of the magnetic field along these sides is given by:
∮ B · dl = μ0 * Ienclosed

The left-hand side of the equation is the product of the magnetic field (B) and the length (w) of the sides parallel to the z-axis. The right-hand side is the product of the permeability of free space (μ0) and the current enclosed (Ienclosed).

5. Calculate the magnetic field intensity:
Since the line integral along the sides parallel to the y-axis is zero, we can write the equation as:
B * w + B * w = μ0 * Ienclosed

Simplifying the equation, we get:
2Bw = μ0 * Ienclosed

Solving for B, we have:
B = μ0 * Ienclosed / (2w)

Since the z-component of the field is above the sheet, we can take the width (w) to be infinitesimally small, approaching zero. In this case, the magnetic field intensity becomes:
B = μ0 * Ienclosed / (2 * 0) = ∞

Therefore, the magnetic field intensity due to an infinite sheet of current with a charge density of 12 j units and the z component above the sheet is infinite.
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Find the magnetic field intensity due to an infinite sheet of current 5A and charge density of 12j units in the positive y direction and the z component is above the sheet.a)-6b)12kc)60d)6Correct answer is option 'D'. Can you explain this answer?
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