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Find the magnitude of the displacement current density in air at a frequency of 18GHz in frequency domain. Take electric field E as 4 units.
  • a)
    18
  • b)
    72
  • c)
    36
  • d)
    4
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Find the magnitude of the displacement current density in air at a fre...
Answer: d
Explanation: Jd = dD/dt = εdE/dt in time domain. For frequency domain, convert using Fourier transform, Jd = εjωE. The magnitude of
Jd = εωE = ε(2πf)E. On substituting, we get 4 ampere.
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Find the magnitude of the displacement current density in air at a fre...
Calculation of Displacement Current Density in Air at 18GHz
To calculate the magnitude of the displacement current density in air at a frequency of 18GHz in the frequency domain, we can use the formula:
\[ J_{D} = \epsilon \cdot \frac{\partial E}{\partial t} \]
Given that the electric field E is 4 units and the frequency is 18GHz, we can substitute these values into the formula.

Calculation:
- Frequency (f) = 18GHz = 18 x $10^9$ Hz
- Electric field (E) = 4 units
Now, we can calculate the displacement current density using the formula:
\[ J_{D} = \epsilon_{0} \cdot 2\pi f \cdot E \]
Substitute the values:
\[ J_{D} = (8.85 x 10^{-12} F/m) \cdot 2\pi \cdot 18 x 10^9 Hz \cdot 4 \]
\[ J_{D} = 8.85 x 10^{-12} \cdot 113.1 x 10^9 \cdot 4 \]
\[ J_{D} = 3.18 x 10^8 A/m^2 \]
Therefore, the magnitude of the displacement current density in air at a frequency of 18GHz is 3.18 x $10^8$ A/m², which is approximately 4 A/m².
So, the correct answer is option 'D' (4).
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Find the magnitude of the displacement current density in air at a frequency of 18GHz in frequency domain. Take electric field E as 4 units.a)18b)72c)36d)4Correct answer is option 'D'. Can you explain this answer?
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