The students of three classes, A, B and C take a test. The average mar...
Let the number of students in the three classes be nA, nB and nc and the total scores of students In the three classes be Ta, Tb and Tc respectively.
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The students of three classes, A, B and C take a test. The average mar...
Given:
- Average marks per student of classes A and B together = 71
- Average marks per student of classes B and C together = 76
- Average marks per student of classes A and C together = 79
To find: Range of the average marks of all three classes put together
Approach:
Let's assume the number of students in classes A, B and C to be a, b, and c respectively. Then, we can use the following formula to find the average marks:
Average marks = Total marks / Number of students
Using this formula, we can form three equations as follows:
(aA + bB) / (a + b) = 71 ----(1)
(bB + cC) / (b + c) = 76 ----(2)
(aA + cC) / (a + c) = 79 ----(3)
where A, B, and C are the average marks of classes A, B, and C respectively.
Solving these equations, we get:
A = (2a + c - 147) / (a + c - 2b) ----(4)
B = (2b + a + c - 147) / (a + b + c) ----(5)
C = (2c + a - 158) / (a + c - 2b) ----(6)
Now, we can find the range of the average marks as follows:
- Maximum value of the average marks:
The maximum value of the average marks will be when the values of A, B, and C are maximum. From equations (4), (5), and (6), we can see that A and C will be maximum when a > b > c, and B will be maximum when a > c > b. Therefore, we can assume a = b + x and c = b - y, where x > y > 0. Substituting these values in equations (4), (5), and (6), we get:
A = (3b + x - y - 147) / x ----(7)
B = (3b + x - y - 147) / (2b + x - y) ----(8)
C = (3b - x + y - 158) / y ----(9)
To maximize the value of the average marks, we need to maximize the value of (A + B + C) / 3. Substituting equations (7), (8), and (9) in this formula, we get:
(A + B + C) / 3 = (9b - 305) / (3x + 2y) ----(10)
To maximize this value, we need to maximize the value of 9b - 305, which is when b is maximum. Therefore, we can assume b = 100. Substituting this value in equations (7), (8), and (9), we get:
A = (3x - y - 47) / x ----(11)
B = 100 ----(12)
C = (3y - x - 58) / y ----(13)
Substituting equations (11), (12), and (13) in equation (10), we get:
(A + B + C) /