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The students of three classes, A, B and C take a test. The average marks per student of the classes A and B put together is 71. The average marks per student of the classes B and C put together is 76. The average per student marks of the class A and C put together is 79. Find the range of the average marks (p) of all the three classes put together.
  • a)
    72 < p < 76    
  • b)
    73 < p < 75
  • c)
    73.5 < p < 77.5    
  • d)
    71 < p < 77
Correct answer is option 'C'. Can you explain this answer?
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The students of three classes, A, B and C take a test. The average mar...
Let the number of students in the three classes be nA, nB and nc and the total scores of students In the three classes be Ta, Tb and Tc respectively.
 
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Most Upvoted Answer
The students of three classes, A, B and C take a test. The average mar...
Given:
- Average marks per student of classes A and B together = 71
- Average marks per student of classes B and C together = 76
- Average marks per student of classes A and C together = 79

To find: Range of the average marks of all three classes put together

Approach:
Let's assume the number of students in classes A, B and C to be a, b, and c respectively. Then, we can use the following formula to find the average marks:

Average marks = Total marks / Number of students

Using this formula, we can form three equations as follows:

(aA + bB) / (a + b) = 71 ----(1)
(bB + cC) / (b + c) = 76 ----(2)
(aA + cC) / (a + c) = 79 ----(3)

where A, B, and C are the average marks of classes A, B, and C respectively.

Solving these equations, we get:

A = (2a + c - 147) / (a + c - 2b) ----(4)
B = (2b + a + c - 147) / (a + b + c) ----(5)
C = (2c + a - 158) / (a + c - 2b) ----(6)

Now, we can find the range of the average marks as follows:

- Maximum value of the average marks:
The maximum value of the average marks will be when the values of A, B, and C are maximum. From equations (4), (5), and (6), we can see that A and C will be maximum when a > b > c, and B will be maximum when a > c > b. Therefore, we can assume a = b + x and c = b - y, where x > y > 0. Substituting these values in equations (4), (5), and (6), we get:

A = (3b + x - y - 147) / x ----(7)
B = (3b + x - y - 147) / (2b + x - y) ----(8)
C = (3b - x + y - 158) / y ----(9)

To maximize the value of the average marks, we need to maximize the value of (A + B + C) / 3. Substituting equations (7), (8), and (9) in this formula, we get:

(A + B + C) / 3 = (9b - 305) / (3x + 2y) ----(10)

To maximize this value, we need to maximize the value of 9b - 305, which is when b is maximum. Therefore, we can assume b = 100. Substituting this value in equations (7), (8), and (9), we get:

A = (3x - y - 47) / x ----(11)
B = 100 ----(12)
C = (3y - x - 58) / y ----(13)

Substituting equations (11), (12), and (13) in equation (10), we get:

(A + B + C) /
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The students of three classes, A, B and C take a test. The average marks per student of the classes A and B put together is 71. The average marks per student of the classes B and C put together is 76. The average per student marks of the class A and C put together is 79. Find the range of the average marks (p) of all the three classes put together.a)72 < p < 76 b)73 < p < 75c)73.5 < p < 77.5 d)71 < p < 77Correct answer is option 'C'. Can you explain this answer?
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The students of three classes, A, B and C take a test. The average marks per student of the classes A and B put together is 71. The average marks per student of the classes B and C put together is 76. The average per student marks of the class A and C put together is 79. Find the range of the average marks (p) of all the three classes put together.a)72 < p < 76 b)73 < p < 75c)73.5 < p < 77.5 d)71 < p < 77Correct answer is option 'C'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The students of three classes, A, B and C take a test. The average marks per student of the classes A and B put together is 71. The average marks per student of the classes B and C put together is 76. The average per student marks of the class A and C put together is 79. Find the range of the average marks (p) of all the three classes put together.a)72 < p < 76 b)73 < p < 75c)73.5 < p < 77.5 d)71 < p < 77Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The students of three classes, A, B and C take a test. The average marks per student of the classes A and B put together is 71. The average marks per student of the classes B and C put together is 76. The average per student marks of the class A and C put together is 79. Find the range of the average marks (p) of all the three classes put together.a)72 < p < 76 b)73 < p < 75c)73.5 < p < 77.5 d)71 < p < 77Correct answer is option 'C'. Can you explain this answer?.
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