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Total number of geometrical isomers for the complex [RhCl(CO)(PPh3)(NH3)]is
  • a)
    3
  • b)
    1
  • c)
    2
  • d)
    4
Correct answer is option 'A'. Can you explain this answer?
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Total number of geometrical isomers for the complex [RhCl(CO)(PPh3)(NH...
The total number of geometrical isomers for the complex [RhCl(CO)(PPh3​)(NH3)] is since it is a square planar. 
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Total number of geometrical isomers for the complex [RhCl(CO)(PPh3)(NH...
Geometrical isomers in coordination compounds

Geometrical isomers are coordination compounds that have the same molecular formula but differ in the arrangement of ligands around the central metal atom.

Factors that influence the formation of geometrical isomers include:

- The presence of at least two different ligands that can occupy the same coordination site
- The presence of a chiral center in the ligand or the metal atom
- The type of ligand and the coordination number of the metal atom

Complex [RhCl(CO)(PPh3)(NH3)]

The complex [RhCl(CO)(PPh3)(NH3)] has a rhodium atom at its center, coordinated to four ligands:

- Chloride ion (Cl-)
- Carbon monoxide (CO)
- Triphenylphosphine (PPh3)
- Ammonia (NH3)

This complex has a square planar geometry, with the four ligands arranged around the rhodium atom in a plane.

Geometrical isomers in [RhCl(CO)(PPh3)(NH3)]

To determine the number of geometrical isomers in the complex [RhCl(CO)(PPh3)(NH3)], we need to identify the possible arrangements of the ligands around the rhodium atom.

There are two types of ligands in this complex that can occupy the same coordination site:

- Chloride ion (Cl-) and carbon monoxide (CO)
- Triphenylphosphine (PPh3) and ammonia (NH3)

Therefore, we can have two different arrangements of these ligands around the rhodium atom:

- Cl and CO in cis position, PPh3 and NH3 in trans position
- Cl and CO in trans position, PPh3 and NH3 in cis position

Each of these arrangements can also have a mirror image, resulting in a total of four possible geometrical isomers:

- cis-[RhCl(CO)(PPh3)(NH3)]
- trans-[RhCl(CO)(PPh3)(NH3)]
- cis-[RhCl(CO)(NH3)(PPh3)]
- trans-[RhCl(CO)(NH3)(PPh3)]

Therefore, the correct answer is option A, 3 geometrical isomers.
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