Electronics and Communication Engineering (ECE) Exam > Electronics and Communication Engineering (ECE) Questions > A 555 astable oscillator with R1= 40 kΩ,...
Start Learning for Free
A 555 astable oscillator with R1 = 40 kΩ, R2 = 120 kΩ and C = 4.0 μF will oscillate at
- a)1.288 Hz
- b)443.5 Hz
- c)443.5 kHz
- d)1.288 kHz
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = ...
Most Upvoted Answer
A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = ...
Understanding the 555 Astable Oscillator
The 555 timer in astable mode functions as an oscillator, generating a continuous square wave signal. The frequency of oscillation can be calculated using the formula:
Frequency (f) = 1.44 / ((R1 + 2*R2) * C)
Where:
- R1 = 40 kΩ
- R2 = 120 kΩ
- C = 4.0 F
Calculating the Total Resistance
- Total Resistance (R1 + 2*R2):
- R1 = 40,000 Ω
- R2 = 120,000 Ω
- Therefore, R1 + 2*R2 = 40,000 + 2*120,000 = 40,000 + 240,000 = 280,000 Ω
Calculating the Frequency
- Substituting the values into the frequency formula:
- f = 1.44 / (280,000 * 4.0)
- f = 1.44 / 1,120,000
- f = 0.0000012857 Hz
- Converting to Hz:
- f ≈ 1.288 Hz
Conclusion
The calculated frequency of oscillation for the given 555 astable oscillator configuration is approximately 1.288 Hz. Thus, the correct answer to the question is option 'A' (1.288 Hz).
Ensure to double-check the component values and calculations in practical applications, as variations in component tolerances can affect performance.
The 555 timer in astable mode functions as an oscillator, generating a continuous square wave signal. The frequency of oscillation can be calculated using the formula:
Frequency (f) = 1.44 / ((R1 + 2*R2) * C)
Where:
- R1 = 40 kΩ
- R2 = 120 kΩ
- C = 4.0 F
Calculating the Total Resistance
- Total Resistance (R1 + 2*R2):
- R1 = 40,000 Ω
- R2 = 120,000 Ω
- Therefore, R1 + 2*R2 = 40,000 + 2*120,000 = 40,000 + 240,000 = 280,000 Ω
Calculating the Frequency
- Substituting the values into the frequency formula:
- f = 1.44 / (280,000 * 4.0)
- f = 1.44 / 1,120,000
- f = 0.0000012857 Hz
- Converting to Hz:
- f ≈ 1.288 Hz
Conclusion
The calculated frequency of oscillation for the given 555 astable oscillator configuration is approximately 1.288 Hz. Thus, the correct answer to the question is option 'A' (1.288 Hz).
Ensure to double-check the component values and calculations in practical applications, as variations in component tolerances can affect performance.
Attention Electronics and Communication Engineering (ECE) Students!
To make sure you are not studying endlessly, EduRev has designed Electronics and Communication Engineering (ECE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electronics and Communication Engineering (ECE).
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Top Courses for Electronics and Communication Engineering (ECE)View all
A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = 4.0 μF will oscillate ata)1.288 Hz b)443.5 Hzc)443.5 kHz d)1.288 kHzCorrect answer is option 'A'. Can you explain this answer?
Question Description
A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = 4.0 μF will oscillate ata)1.288 Hz b)443.5 Hzc)443.5 kHz d)1.288 kHzCorrect answer is option 'A'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = 4.0 μF will oscillate ata)1.288 Hz b)443.5 Hzc)443.5 kHz d)1.288 kHzCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = 4.0 μF will oscillate ata)1.288 Hz b)443.5 Hzc)443.5 kHz d)1.288 kHzCorrect answer is option 'A'. Can you explain this answer?.
A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = 4.0 μF will oscillate ata)1.288 Hz b)443.5 Hzc)443.5 kHz d)1.288 kHzCorrect answer is option 'A'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = 4.0 μF will oscillate ata)1.288 Hz b)443.5 Hzc)443.5 kHz d)1.288 kHzCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = 4.0 μF will oscillate ata)1.288 Hz b)443.5 Hzc)443.5 kHz d)1.288 kHzCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = 4.0 μF will oscillate ata)1.288 Hz b)443.5 Hzc)443.5 kHz d)1.288 kHzCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE).
Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.
Here you can find the meaning of A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = 4.0 μF will oscillate ata)1.288 Hz b)443.5 Hzc)443.5 kHz d)1.288 kHzCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = 4.0 μF will oscillate ata)1.288 Hz b)443.5 Hzc)443.5 kHz d)1.288 kHzCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = 4.0 μF will oscillate ata)1.288 Hz b)443.5 Hzc)443.5 kHz d)1.288 kHzCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = 4.0 μF will oscillate ata)1.288 Hz b)443.5 Hzc)443.5 kHz d)1.288 kHzCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A 555 astable oscillator with R1= 40 kΩ, R2 = 120 kΩand C = 4.0 μF will oscillate ata)1.288 Hz b)443.5 Hzc)443.5 kHz d)1.288 kHzCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
|
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
x
![]()
For Your Perfect Score in Electronics and Communication Engineering (ECE)
The Best you need at One Place
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup