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A, B and C together can complete a work in 25 days. If the ratio of efficiency of A, B and C is 15 ∶ 10 ∶ 6 respectively, then in how many days C alone can complete the same work?
  • a)
    727/6
  • b)
    725/6
  • c)
    775/6
  • d)
    745/6
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A, B and C together can complete a work in 25 days. If the ratio of ef...
Ratio of efficiency of A, B and C = 15 ∶ 10 ∶ 6
Ratio of time of A, B and C = 1/15 ∶ 1/10 ∶ 1/6 = 2 ∶ 3 ∶ 5
Let A alone can complete the work in = 2x days
B alone can complete the work in = 3x days
And C alone can complete the work in = 5x days
According to the question,
1/2x + 1/3x + 1/5x = 1/25
⇒ 31/30x = 1/25
⇒ x = 155/6
So, C alone can complete the work in = 5x = 5 × 155/6 = 775/6 days
Short trick:
Total work = (15 + 10 + 6) × 25 = 31 × 25 = 775
∴ C will complete the work = 775/6
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Most Upvoted Answer
A, B and C together can complete a work in 25 days. If the ratio of ef...
Given, A:B:C = 15:10:6
Let the common ratio be x
Then, A's efficiency = 15x, B's efficiency = 10x, C's efficiency = 6x

Efficiency of A, B and C together = 15x + 10x + 6x = 31x
They can complete the work in 25 days
Therefore, the total work = Efficiency × Time = 31x × 25

To find the number of days taken by C alone to complete the same work:
Let C alone takes 'd' days to complete the work
Then, efficiency of C = Total work / Time = 31x × 25 / d

As per the given ratio, C's efficiency = 6x
Equating the above two equations, we get:
31x × 25 / d = 6x
d = 31 × 25 / 6 = 775/6

Therefore, C alone can complete the work in 775/6 days or 129 1/6 days (approx).
Hence, the correct answer is option C.
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Question Description
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