If each term in the sum a1 + a2 + a3 + ... +an is either 7 or 77 and t...
Solution:
To solve this problem, we need to use a bit of logic and guesswork.
Let's start by assuming that all the terms in the sum are 7. In this case, the sum would be:
7 + 7 + 7 + ... + 7 (n terms) = 7n
We know that the sum is 350, so we can set up the equation:
7n = 350
Solving for n, we get:
n = 50
But we also know that each term is either 7 or 77. So let's assume that all the terms are 77. In this case, the sum would be:
77 + 77 + 77 + ... + 77 (n terms) = 77n
We know that the sum is 350, so we can set up the equation:
77n = 350
Solving for n, we get:
n ≈ 4.55
This doesn't give us a whole number for n, so we need to try something in between. Let's assume that half the terms are 7 and half are 77. In this case, the sum would be:
7 + 77 + 7 + 77 + ... (n terms) = (7 + 77)n/2 = 42n
We know that the sum is 350, so we can set up the equation:
42n = 350
Solving for n, we get:
n ≈ 8.33
Again, we don't get a whole number for n. But notice that as we move from all 7s to all 77s to a mix of 7s and 77s, the value of n is decreasing. So we can make an educated guess that the value of n lies somewhere between 50 and 8.
Looking at the answer choices, we see that only option C (40) falls within this range. Therefore, the correct answer is C.
If each term in the sum a1 + a2 + a3 + ... +an is either 7 or 77 and t...
Easy
one 77 takes 11 ,7s
for 350= 7*5*10,that is 50 7 s are required
if we put as per the options in the range of 40s ,one 77 and 39 7s then n will be 40 and sum will 350