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A narrow band signal occupying a frequency range of nfo to (n + 1) f0 is to be sampled. The maximum sampling rate is
  • a)
    2nf0    
  • b)
    2(n + 1)f0
  • c)
    2f0
  • d)
    f0/2
Correct answer is option 'C'. Can you explain this answer?
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Sampling Rate Calculation for Narrow Band Signal
Sampling rate is determined by the Nyquist theorem, which states that the sampling rate must be at least twice the highest frequency component in the signal being sampled.

Given Information:
- Narrow band signal occupying a frequency range of nfo to (n + 1) f0

Maximum Sampling Rate Calculation:
- The maximum frequency in the signal is (n + 1) f0
- According to Nyquist theorem, the sampling rate should be at least twice this maximum frequency
- Therefore, the maximum sampling rate is 2(n + 1) f0

Options Explanation:
- Option (a) 2nf0 is incorrect as it does not take into account the full frequency range of the signal
- Option (b) 2(n + 1)f0 is also incorrect as it is equivalent to the maximum frequency, not the sampling rate
- Option (d) f0/2 is incorrect as it is below the minimum required sampling rate

Correct Answer:
- Option (c) 2f0 is the correct answer as it represents the maximum sampling rate required for the given narrow band signal.
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A narrow band signal occupying a frequency range of nfo to (n + 1) f0 is to be sampled. The maximum sampling rate isa)2nf0 b)2(n + 1)f0c)2f0d)f0/2Correct answer is option 'C'. Can you explain this answer?
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