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A particular green LED emits light of wavelength 4970 A°. The energy band gap of the semiconductor material used in LED is (plank’s constant = 6.626 x 10-34 J -s)
  • a)
    0.74eV
  • b)
    1.17eV
  • c)
    2.49eV
  • d)
    3.98eV
Correct answer is option 'C'. Can you explain this answer?
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Calculation of Energy Band Gap

Given: Wavelength of emitted light, λ = 4970 A = 4970 x 10^-10 m

Planck's constant, h = 6.626 x 10^-34 J-s

We know that the energy of a photon is given by E = hc/λ, where c is the speed of light in vacuum.

Therefore, the energy of the photon emitted by the LED is:

E = hc/λ

E = (6.626 x 10^-34 J-s) x (3 x 10^8 m/s) / (4970 x 10^-10 m)

E = 3.99 x 10^-19 J

We also know that the energy of a photon is related to the energy band gap of the semiconductor material by E = Eg + Ef, where Eg is the energy band gap and Ef is the Fermi level.

Since the Fermi level is constant for a given material, we can assume that Ef = 0.

Therefore, Eg = E - Ef = E = 3.99 x 10^-19 J

Converting this energy into electron volts (eV), we get:

1 eV = 1.602 x 10^-19 J

Eg = (3.99 x 10^-19 J) / (1.602 x 10^-19 J/eV)

Eg = 2.49 eV

Therefore, the energy band gap of the semiconductor material used in the LED is 2.49 eV.
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A particular green LED emits light of wavelength 4970 A°. The energy band gap of the semiconductor material used in LED is (plank’s constant = 6.626 x 10-34 J -s)a)0.74eVb)1.17eVc)2.49eVd)3.98eVCorrect answer is option 'C'. Can you explain this answer?
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