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Two vessels. A and B, each of volume 3m3 be connected by a tube of negligible volume. Vessel A contains air at 0.7 mPa, 950C. while vessel B contains air at 0.35 mPa, 2050C. The change of entropy when A is connected to B by working from the first principles and assuming the mixing to be complete and adiabatic is _____.[c = 1.005 KJ/kg.k,cv=0.718KJ/kg.k, R = 0.287KJ/kg.k]
    Correct answer is '0.96'. Can you explain this answer?
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    Two vessels. A and B, each of volume 3m3 be connected by a tube of neg...
    Let the final temperature be Tf



    for adiabatic mixing of gas Internal Energy must be same uA = mAcVTA
    = 19.88335 x 0.718 x 368 KT = 5253.66 KJ

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    Two vessels. A and B, each of volume 3m3 be connected by a tube of neg...
    Given:
    - Vessel A volume (VA) = 3 m3
    - Vessel B volume (VB) = 3 m3
    - Pressure in vessel A (PA) = 0.7 mPa
    - Pressure in vessel B (PB) = 0.35 mPa
    - Temperature in vessel A (TA) = 950°C = 950 + 273 = 1223 K
    - Temperature in vessel B (TB) = 2050°C = 2050 + 273 = 2323 K
    - Specific heat capacity at constant volume (cv) = 0.718 KJ/kg·K
    - Specific heat capacity at constant pressure (cp) = 1.005 KJ/kg·K
    - Gas constant (R) = 0.287 KJ/kg·K

    To find:
    Change in entropy when vessel A is connected to vessel B (ΔS)

    Solution:
    Step 1: Calculate the number of moles in each vessel using the ideal gas equation:
    - Moles in vessel A (nA) = (PA * VA) / (R * TA)
    - Moles in vessel B (nB) = (PB * VB) / (R * TB)

    Step 2: Calculate the total number of moles after mixing:
    - Total moles (ntotal) = nA + nB

    Step 3: Calculate the final pressure (Pfinal) using the ideal gas equation:
    - Pfinal = (ntotal * R * TB) / (VA + VB)

    Step 4: Calculate the change in entropy using the equation:
    - ΔS = nA * cv * ln(Tfinal / TA) + nB * cv * ln(Tfinal / TB)

    Step 5: Substitute the given values into the equations and calculate the change in entropy:
    - Moles in vessel A (nA) = (0.7 * 3) / (0.287 * 1223) = 0.0655 kg
    - Moles in vessel B (nB) = (0.35 * 3) / (0.287 * 2323) = 0.0211 kg
    - Total moles (ntotal) = 0.0655 + 0.0211
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    Two vessels. A and B, each of volume 3m3 be connected by a tube of negligible volume. Vessel A contains air at 0.7 mPa, 950C. while vessel B contains airat 0.35 mPa, 2050C. The change of entropy when A is connected to B by working from the first principles and assuming the mixing to be complete and adiabatic is _____.[c = 1.005 KJ/kg.k,cv=0.718KJ/kg.k, R = 0.287KJ/kg.k]Correct answer is '0.96'. Can you explain this answer?
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    Two vessels. A and B, each of volume 3m3 be connected by a tube of negligible volume. Vessel A contains air at 0.7 mPa, 950C. while vessel B contains airat 0.35 mPa, 2050C. The change of entropy when A is connected to B by working from the first principles and assuming the mixing to be complete and adiabatic is _____.[c = 1.005 KJ/kg.k,cv=0.718KJ/kg.k, R = 0.287KJ/kg.k]Correct answer is '0.96'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Two vessels. A and B, each of volume 3m3 be connected by a tube of negligible volume. Vessel A contains air at 0.7 mPa, 950C. while vessel B contains airat 0.35 mPa, 2050C. The change of entropy when A is connected to B by working from the first principles and assuming the mixing to be complete and adiabatic is _____.[c = 1.005 KJ/kg.k,cv=0.718KJ/kg.k, R = 0.287KJ/kg.k]Correct answer is '0.96'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two vessels. A and B, each of volume 3m3 be connected by a tube of negligible volume. Vessel A contains air at 0.7 mPa, 950C. while vessel B contains airat 0.35 mPa, 2050C. The change of entropy when A is connected to B by working from the first principles and assuming the mixing to be complete and adiabatic is _____.[c = 1.005 KJ/kg.k,cv=0.718KJ/kg.k, R = 0.287KJ/kg.k]Correct answer is '0.96'. Can you explain this answer?.
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