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Machines P, Q and R can do a piece of work in 20, 30 and 60 days respectively. Machines P, Q and R start the work together. Machine P goes out of order after 5 days. After 3 more days machines Q and R also go out of order. Machine P got repaired by then and it completes the remaining work. What portion of the total work did machine P do?
- a)3/4
- b)11/20
- c)7/20
- d)3/5
Correct answer is option 'D'. Can you explain this answer?
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Machines P, Q and R can do a piece of work in 20, 30 and 60 days respe...
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Machines P, Q and R can do a piece of work in 20, 30 and 60 days respe...
Given information:
- Machine P can complete the work in 20 days.
- Machine Q can complete the work in 30 days.
- Machine R can complete the work in 60 days.
Let's calculate the work done by each machine in 1 day:
- Machine P can do 1/20th of the work in 1 day.
- Machine Q can do 1/30th of the work in 1 day.
- Machine R can do 1/60th of the work in 1 day.
Calculating work done by all machines together in 1 day:
- (1/20 + 1/30 + 1/60) = (3/60 + 2/60 + 1/60) = 6/60 = 1/10
Work done by all machines together in 8 days (before any machine goes out of order):
- 8 × (1/10) = 8/10 = 4/5
Machine P goes out of order after 5 days, so the work done by all machines together in 5 days:
- 5 × (1/10) = 1/2
Now, machines Q and R continue working for 3 more days (after machine P goes out of order):
- 3 × ((1/30) + (1/60)) = 3 × (2/60) = 1/10
Total work done by all machines before machine P gets repaired:
- (4/5 + 1/2 + 1/10) = (8/10 + 5/10 + 1/10) = 14/10 = 7/5
Remaining work to be done after machine P gets repaired:
- 1 - (7/5) = 5/5 - 7/5 = -2/5
Since the remaining work cannot be negative, it means that the work done by machine P is equal to the total work done before it gets repaired.
Therefore, the portion of the total work done by machine P is:
- (7/5) / (7/5) = 1
Hence, the correct answer is option D) 3/5.
- Machine P can complete the work in 20 days.
- Machine Q can complete the work in 30 days.
- Machine R can complete the work in 60 days.
Let's calculate the work done by each machine in 1 day:
- Machine P can do 1/20th of the work in 1 day.
- Machine Q can do 1/30th of the work in 1 day.
- Machine R can do 1/60th of the work in 1 day.
Calculating work done by all machines together in 1 day:
- (1/20 + 1/30 + 1/60) = (3/60 + 2/60 + 1/60) = 6/60 = 1/10
Work done by all machines together in 8 days (before any machine goes out of order):
- 8 × (1/10) = 8/10 = 4/5
Machine P goes out of order after 5 days, so the work done by all machines together in 5 days:
- 5 × (1/10) = 1/2
Now, machines Q and R continue working for 3 more days (after machine P goes out of order):
- 3 × ((1/30) + (1/60)) = 3 × (2/60) = 1/10
Total work done by all machines before machine P gets repaired:
- (4/5 + 1/2 + 1/10) = (8/10 + 5/10 + 1/10) = 14/10 = 7/5
Remaining work to be done after machine P gets repaired:
- 1 - (7/5) = 5/5 - 7/5 = -2/5
Since the remaining work cannot be negative, it means that the work done by machine P is equal to the total work done before it gets repaired.
Therefore, the portion of the total work done by machine P is:
- (7/5) / (7/5) = 1
Hence, the correct answer is option D) 3/5.
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Machines P, Q and R can do a piece of work in 20, 30 and 60 days respectively. Machines P, Q and R start the work together. Machine P goes out of order after 5 days. After 3 more days machines Q and R also go out of order. Machine P got repaired by then and it completes the remaining work. What portion of the total work did machine P do?a)3/4 b)11/20 c)7/20 d)3/5Correct answer is option 'D'. Can you explain this answer?
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Machines P, Q and R can do a piece of work in 20, 30 and 60 days respectively. Machines P, Q and R start the work together. Machine P goes out of order after 5 days. After 3 more days machines Q and R also go out of order. Machine P got repaired by then and it completes the remaining work. What portion of the total work did machine P do?a)3/4 b)11/20 c)7/20 d)3/5Correct answer is option 'D'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Machines P, Q and R can do a piece of work in 20, 30 and 60 days respectively. Machines P, Q and R start the work together. Machine P goes out of order after 5 days. After 3 more days machines Q and R also go out of order. Machine P got repaired by then and it completes the remaining work. What portion of the total work did machine P do?a)3/4 b)11/20 c)7/20 d)3/5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Machines P, Q and R can do a piece of work in 20, 30 and 60 days respectively. Machines P, Q and R start the work together. Machine P goes out of order after 5 days. After 3 more days machines Q and R also go out of order. Machine P got repaired by then and it completes the remaining work. What portion of the total work did machine P do?a)3/4 b)11/20 c)7/20 d)3/5Correct answer is option 'D'. Can you explain this answer?.
Machines P, Q and R can do a piece of work in 20, 30 and 60 days respectively. Machines P, Q and R start the work together. Machine P goes out of order after 5 days. After 3 more days machines Q and R also go out of order. Machine P got repaired by then and it completes the remaining work. What portion of the total work did machine P do?a)3/4 b)11/20 c)7/20 d)3/5Correct answer is option 'D'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Machines P, Q and R can do a piece of work in 20, 30 and 60 days respectively. Machines P, Q and R start the work together. Machine P goes out of order after 5 days. After 3 more days machines Q and R also go out of order. Machine P got repaired by then and it completes the remaining work. What portion of the total work did machine P do?a)3/4 b)11/20 c)7/20 d)3/5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Machines P, Q and R can do a piece of work in 20, 30 and 60 days respectively. Machines P, Q and R start the work together. Machine P goes out of order after 5 days. After 3 more days machines Q and R also go out of order. Machine P got repaired by then and it completes the remaining work. What portion of the total work did machine P do?a)3/4 b)11/20 c)7/20 d)3/5Correct answer is option 'D'. Can you explain this answer?.
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