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Consider a solid sphere of radius 5 cm made of a perfect electric conductor. If one million electrons are added to this sphere, these electrons will be distributed.
  • a)
    uniformly over the entire volume of the sphere
  • b)
    uniformly over the outer surface of the sphere
  • c)
    concentrated around the centre of the sphere
  • d)
    along a straight line passing through the centre of the sphere
Correct answer is option 'B'. Can you explain this answer?
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Consider a solid sphere of radius 5 cm made of a perfect electric cond...
For a perfect conductor the charge is present only on the surface.
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Consider a solid sphere of radius 5 cm made of a perfect electric cond...
Answer:

To determine the distribution of electrons on the solid sphere, we need to consider the behavior of electric charges on a conductor. When a conductor is in electrostatic equilibrium, the charges reside on the outer surface of the conductor. This is known as the "Faraday Cage" effect.

Explanation:

1. Electric Charge Distribution on a Conductor:

- In a conductor, the electrons are free to move within the material. When a conductor is brought into an electric field, the free electrons redistribute themselves on the surface of the conductor until the electric field inside the conductor becomes zero.
- This redistribution of electrons leads to an excess of negative charge on the surface of the conductor, creating an electric field that cancels out the electric field due to the external charges.
- In electrostatic equilibrium, the electric field inside the conductor is zero, and the charges reside on the outer surface of the conductor.

2. Solid Sphere of Perfect Electric Conductor:

- In the given scenario, we have a solid sphere made of a perfect electric conductor. Since it is a perfect conductor, the electrons are free to move within the material.
- When one million electrons are added to the sphere, they will redistribute themselves on the outer surface of the sphere due to the electric repulsion between them.
- The excess negative charge will accumulate on the outer surface of the sphere, while the inner volume of the sphere will have a neutral charge distribution.
- This distribution is possible because the sphere is a conductor, allowing the electrons to move freely on its surface and redistribute themselves to cancel out the electric field inside the conductor.

3. Distribution of Electrons:

- As a result, the electrons will be uniformly distributed over the outer surface of the sphere. This means that each unit area on the outer surface will have an equal number of electrons.
- The distribution will be such that the electric field inside the sphere is zero, and the charges on the outer surface create an electric field that cancels out the electric field due to the added electrons.
- The electrons will not be concentrated around the center of the sphere because the electric repulsion between them will cause them to spread out evenly on the outer surface.
- Similarly, the electrons will not be distributed along a straight line passing through the center of the sphere because they will repel each other and spread out over the curved surface of the sphere.

Hence, the correct answer is option 'B' - the electrons will be uniformly distributed over the outer surface of the sphere.
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it depends on the length of the conductor the capacitance of the line is proportional to the length of the transmission line their effect is negligible on the performance of short having a length less than 80 km and low voltage transmission accidents of the transmission line along with the conductances forms the shunted mittens the conductance and the transmission line is because of the leakage over the surface of the conductor considered a line consisting of two conductors and be each of radius are the distance between the conductors being Des shown in the diagram below minus the potential difference between the conductors and via's work QA charge on conductor QB charge on conductor vvab pencil difference between conductor and the Epsilon minus absolute primitivity QA plus QV = 0 so that QA equals QB - equals DBA equals data equals DB equals our substituting these values and voltage equation we get the capacitance between the conductors is cab is referred to as lying to line capacitance if the two conductors are in VR oppositely charge then the potential difference between them is zero then the potential of each conductor is given by one half bath the capacitance between each conductor and point of zero potential and is capacitive CN is called the capacitance to neut or capacitance to ground capacitance cab is the combination of two equal capacity and VN series thus capacitance to neutral is twice the capacitance between the conductors IE CN equals to Cave the absolute primitivity Epsilon is given by Epsilon equals epsilono Epsilon are where epsilano is the permittivity of the free space and Epsilon or is the relative primitivity of the medium prayer capacitance reactants between one conductor and neutral capacitance of the symmetrical three phase line let a balanced system of voltage be applied to a symmetrical three-phase line shown below the phasor diagram of the three phase line with equilateral spacing is shown below take the voltage of conductor to neutral as a reference phaser the potential difference between conductor and we can be written the similarly potential difference between conductors and sea is on adding equations one and two we get also combining equation three and four from equation 6 and 7 the line to neutral capacitance the capacitance of symmetrical three phase line is same as that of the two wire line Related: Capacitance of Transmission Lines?

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Consider a solid sphere of radius 5 cm made of a perfect electric conductor. If one million electrons are added to this sphere, these electrons will be distributed.a)uniformly over the entire volume of the sphereb)uniformly over the outer surface of the spherec)concentrated around the centre of the sphered)along a straight line passing through the centre of the sphereCorrect answer is option 'B'. Can you explain this answer?
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