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The following program is run on an 8085 microprocessor:
Memory Address Instruction
(in hex)
3000 LXI SP, 4000
3003 PUSH H
3004 PUSH D
3005 CALL 3050
3008 POP H
3009 HLT
At the completion of execution of the program, the program counter of 8085 and stack pointer contains
- a)3050, 3FFB
- b)3051, 3FFC
- c)3050, 3FFC
- d)3051, 3FFB
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The following program is run on an 8085 microprocessor:Memory Address ...
(c)
3000 SP → 4 4000
3003 SP → SP decremented by 2 i_e_ 3FFE
3004 SP → SP decremented by 2 3FFC
3005 PC → 3050
SP → 3FFC
PC → 3050
Most Upvoted Answer
The following program is run on an 8085 microprocessor:Memory Address ...
Program Execution:
Let's analyze the given program step by step to understand its execution and determine the final values of the program counter (PC) and stack pointer (SP).
1. LXI SP, 4000:
- The instruction "LXI SP, 4000" loads the stack pointer with the value 4000.
- This means that the stack pointer (SP) is initialized with the value 4000.
2. PUSH H:
- The instruction "PUSH H" pushes the contents of the H register onto the stack.
- The stack pointer is decremented by 2 (as it is a 16-bit value) to point to the next available memory location.
- The value of H register is then stored at the memory location pointed by the stack pointer (i.e., 3FFE).
- The stack pointer (SP) becomes 3FFE.
3. PUSH D:
- The instruction "PUSH D" pushes the contents of the D register onto the stack.
- The stack pointer is decremented by 2 to point to the next available memory location.
- The value of D register is then stored at the memory location pointed by the stack pointer (i.e., 3FFC).
- The stack pointer (SP) becomes 3FFC.
4. CALL 3050:
- The instruction "CALL 3050" pushes the return address onto the stack and performs an unconditional jump to the specified memory address.
- The return address is the address of the next instruction after the CALL instruction, which is 3008.
- The stack pointer is decremented by 2 to point to the next available memory location.
- The value of the program counter (PC) is then stored at the memory location pointed by the stack pointer (i.e., 3FFA).
- The stack pointer (SP) becomes 3FFA.
- The program counter (PC) is updated with the specified memory address, 3050, and program execution continues from that address.
5. POP H:
- The instruction "POP H" pops the topmost value from the stack into the H register.
- The value at the memory location pointed by the stack pointer (i.e., 3FFA) is loaded into the H register.
- The stack pointer is incremented by 2 to point to the next value on the stack.
- The stack pointer (SP) becomes 3FFC.
6. HLT:
- The instruction "HLT" halts the program execution.
Final Values:
After the completion of the program execution, the final values of the program counter (PC) and stack pointer (SP) are as follows:
- Program Counter (PC): 3050
- The last executed instruction was "POP H", which updates the program counter (PC) with the next instruction address, 3050.
- Stack Pointer (SP): 3FFC
- The last executed instruction was "POP H", which increments the stack pointer (SP) by 2.
Therefore, the correct answer is option (C) 3050, 3FFC.
Let's analyze the given program step by step to understand its execution and determine the final values of the program counter (PC) and stack pointer (SP).
1. LXI SP, 4000:
- The instruction "LXI SP, 4000" loads the stack pointer with the value 4000.
- This means that the stack pointer (SP) is initialized with the value 4000.
2. PUSH H:
- The instruction "PUSH H" pushes the contents of the H register onto the stack.
- The stack pointer is decremented by 2 (as it is a 16-bit value) to point to the next available memory location.
- The value of H register is then stored at the memory location pointed by the stack pointer (i.e., 3FFE).
- The stack pointer (SP) becomes 3FFE.
3. PUSH D:
- The instruction "PUSH D" pushes the contents of the D register onto the stack.
- The stack pointer is decremented by 2 to point to the next available memory location.
- The value of D register is then stored at the memory location pointed by the stack pointer (i.e., 3FFC).
- The stack pointer (SP) becomes 3FFC.
4. CALL 3050:
- The instruction "CALL 3050" pushes the return address onto the stack and performs an unconditional jump to the specified memory address.
- The return address is the address of the next instruction after the CALL instruction, which is 3008.
- The stack pointer is decremented by 2 to point to the next available memory location.
- The value of the program counter (PC) is then stored at the memory location pointed by the stack pointer (i.e., 3FFA).
- The stack pointer (SP) becomes 3FFA.
- The program counter (PC) is updated with the specified memory address, 3050, and program execution continues from that address.
5. POP H:
- The instruction "POP H" pops the topmost value from the stack into the H register.
- The value at the memory location pointed by the stack pointer (i.e., 3FFA) is loaded into the H register.
- The stack pointer is incremented by 2 to point to the next value on the stack.
- The stack pointer (SP) becomes 3FFC.
6. HLT:
- The instruction "HLT" halts the program execution.
Final Values:
After the completion of the program execution, the final values of the program counter (PC) and stack pointer (SP) are as follows:
- Program Counter (PC): 3050
- The last executed instruction was "POP H", which updates the program counter (PC) with the next instruction address, 3050.
- Stack Pointer (SP): 3FFC
- The last executed instruction was "POP H", which increments the stack pointer (SP) by 2.
Therefore, the correct answer is option (C) 3050, 3FFC.
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The following program is run on an 8085 microprocessor:Memory Address Instruction(in hex)3000 LXI SP, 40003003 PUSH H3004 PUSH D3005 CALL 30503008 POP H3009 HLTAt the completion of execution of the program, the program counter of 8085 and stack pointer containsa)3050, 3FFBb)3051, 3FFCc)3050, 3FFCd)3051, 3FFBCorrect answer is option 'C'. Can you explain this answer?
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The following program is run on an 8085 microprocessor:Memory Address Instruction(in hex)3000 LXI SP, 40003003 PUSH H3004 PUSH D3005 CALL 30503008 POP H3009 HLTAt the completion of execution of the program, the program counter of 8085 and stack pointer containsa)3050, 3FFBb)3051, 3FFCc)3050, 3FFCd)3051, 3FFBCorrect answer is option 'C'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The following program is run on an 8085 microprocessor:Memory Address Instruction(in hex)3000 LXI SP, 40003003 PUSH H3004 PUSH D3005 CALL 30503008 POP H3009 HLTAt the completion of execution of the program, the program counter of 8085 and stack pointer containsa)3050, 3FFBb)3051, 3FFCc)3050, 3FFCd)3051, 3FFBCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The following program is run on an 8085 microprocessor:Memory Address Instruction(in hex)3000 LXI SP, 40003003 PUSH H3004 PUSH D3005 CALL 30503008 POP H3009 HLTAt the completion of execution of the program, the program counter of 8085 and stack pointer containsa)3050, 3FFBb)3051, 3FFCc)3050, 3FFCd)3051, 3FFBCorrect answer is option 'C'. Can you explain this answer?.
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