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Solving Poisson's equation 
for the electrostatic potential 
in a region with a constant charge density 
two students find different answers.
The reason why these different solutions are both correct is because
for the electrostatic potential in a region with a constant charge density two students find different answers. The reason why these different solutions are both correct is because
- a)space is isotropic and hence x and y are physically equivalent.
- b)W e can add solutions of Laplace’s equation to both
- c)The electrostatic energy is infinite for a constant charge density.
- d)The boundary conditions are different in the two cases.
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Solving Poisson's equationfor the electrostatic potentialin a regi...
We know that the poission's equation is
If a potential function
satisfied the Laplace equation 
then
If means that the given potential function will exist in a charge less system. If not. then it will satisfies the poission's equation and we can calculate the charge density (ρ)
The given function are
But the boundary conditions are different in both cases. The boundary condition are along to x-axis. But one function satisfies by the Laplace's eq. and one function satisfies by the Poisson's eq. so we cannot add both solutions.
If a potential function
satisfied the Laplace equation thenIf means that the given potential function will exist in a charge less system. If not. then it will satisfies the poission's equation and we can calculate the charge density (ρ)
The given function are
But the boundary conditions are different in both cases. The boundary condition are along to x-axis. But one function satisfies by the Laplace's eq. and one function satisfies by the Poisson's eq. so we cannot add both solutions.
Most Upvoted Answer
Solving Poisson's equationfor the electrostatic potentialin a regi...
We know that the poission's equation is
If a potential function satisfied the Laplace equation then
If means that the given potential function will exist in a charge less system. If not. then it will satisfies the poission's equation and we can calculate the charge density (ρ)
The given function are
But the boundary conditions are different in both cases. The boundary condition are along to x-axis. But one function satisfies by the Laplace's eq. and one function satisfies by the Poisson's eq. so we cannot add both solutions.
If a potential function
satisfied the Laplace equation thenIf means that the given potential function will exist in a charge less system. If not. then it will satisfies the poission's equation and we can calculate the charge density (ρ)
The given function are
But the boundary conditions are different in both cases. The boundary condition are along to x-axis. But one function satisfies by the Laplace's eq. and one function satisfies by the Poisson's eq. so we cannot add both solutions.
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Community Answer
Solving Poisson's equationfor the electrostatic potentialin a regi...
We know that the poission's equation is
If a potential function satisfied the Laplace equation then
If means that the given potential function will exist in a charge less system. If not. then it will satisfies the poission's equation and we can calculate the charge density (ρ)
The given function are
But the boundary conditions are different in both cases. The boundary condition are along to x-axis. But one function satisfies by the Laplace's eq. and one function satisfies by the Poisson's eq. so we cannot add both solutions.
If a potential function
satisfied the Laplace equation thenIf means that the given potential function will exist in a charge less system. If not. then it will satisfies the poission's equation and we can calculate the charge density (ρ)
The given function are
But the boundary conditions are different in both cases. The boundary condition are along to x-axis. But one function satisfies by the Laplace's eq. and one function satisfies by the Poisson's eq. so we cannot add both solutions.
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Solving Poisson's equationfor the electrostatic potentialin a region with a constant charge densitytwo students find different answers.The reason why these different solutions are both correct is becausea)space is isotropic and hence x and y are physically equivalent.b)W e can add solutions of Laplace’s equation to bothc)The electrostatic energy is infinite for a constant charge density.d)The boundary conditions are different in the two cases.Correct answer is option 'D'. Can you explain this answer?
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Solving Poisson's equationfor the electrostatic potentialin a region with a constant charge densitytwo students find different answers.The reason why these different solutions are both correct is becausea)space is isotropic and hence x and y are physically equivalent.b)W e can add solutions of Laplace’s equation to bothc)The electrostatic energy is infinite for a constant charge density.d)The boundary conditions are different in the two cases.Correct answer is option 'D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Solving Poisson's equationfor the electrostatic potentialin a region with a constant charge densitytwo students find different answers.The reason why these different solutions are both correct is becausea)space is isotropic and hence x and y are physically equivalent.b)W e can add solutions of Laplace’s equation to bothc)The electrostatic energy is infinite for a constant charge density.d)The boundary conditions are different in the two cases.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Solving Poisson's equationfor the electrostatic potentialin a region with a constant charge densitytwo students find different answers.The reason why these different solutions are both correct is becausea)space is isotropic and hence x and y are physically equivalent.b)W e can add solutions of Laplace’s equation to bothc)The electrostatic energy is infinite for a constant charge density.d)The boundary conditions are different in the two cases.Correct answer is option 'D'. Can you explain this answer?.
Solving Poisson's equationfor the electrostatic potentialin a region with a constant charge densitytwo students find different answers.The reason why these different solutions are both correct is becausea)space is isotropic and hence x and y are physically equivalent.b)W e can add solutions of Laplace’s equation to bothc)The electrostatic energy is infinite for a constant charge density.d)The boundary conditions are different in the two cases.Correct answer is option 'D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Solving Poisson's equationfor the electrostatic potentialin a region with a constant charge densitytwo students find different answers.The reason why these different solutions are both correct is becausea)space is isotropic and hence x and y are physically equivalent.b)W e can add solutions of Laplace’s equation to bothc)The electrostatic energy is infinite for a constant charge density.d)The boundary conditions are different in the two cases.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Solving Poisson's equationfor the electrostatic potentialin a region with a constant charge densitytwo students find different answers.The reason why these different solutions are both correct is becausea)space is isotropic and hence x and y are physically equivalent.b)W e can add solutions of Laplace’s equation to bothc)The electrostatic energy is infinite for a constant charge density.d)The boundary conditions are different in the two cases.Correct answer is option 'D'. Can you explain this answer?.
Solutions for Solving Poisson's equationfor the electrostatic potentialin a region with a constant charge densitytwo students find different answers.The reason why these different solutions are both correct is becausea)space is isotropic and hence x and y are physically equivalent.b)W e can add solutions of Laplace’s equation to bothc)The electrostatic energy is infinite for a constant charge density.d)The boundary conditions are different in the two cases.Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Physics.
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