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Solving Poisson's equation  for the electrostatic potential  in a region with a constant charge density  two students find different answers. 

The reason why these different solutions are both correct is because
  • a)
    space is isotropic and hence x and y are physically equivalent.
  • b)
    W e can add solutions of Laplace’s equation to both 
  • c)
    The electrostatic energy is infinite for a constant charge density.
  • d)
    The boundary conditions are different in the two cases.
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Solving Poisson's equationfor the electrostatic potentialin a regi...
We know that the poission's equation is

If a potential function  satisfied the Laplace equation  then
If means that the given potential function will exist in a charge less system. If not. then it will satisfies the poission's equation and we can calculate the charge density (ρ)
The given function are

But the boundary conditions are different in both cases. The boundary condition are along to x-axis. But one function satisfies by the Laplace's eq. and one function satisfies by the Poisson's eq. so we cannot add both solutions.
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Most Upvoted Answer
Solving Poisson's equationfor the electrostatic potentialin a regi...
We know that the poission's equation is

If a potential function  satisfied the Laplace equation  then
If means that the given potential function will exist in a charge less system. If not. then it will satisfies the poission's equation and we can calculate the charge density (ρ)
The given function are

But the boundary conditions are different in both cases. The boundary condition are along to x-axis. But one function satisfies by the Laplace's eq. and one function satisfies by the Poisson's eq. so we cannot add both solutions.
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Community Answer
Solving Poisson's equationfor the electrostatic potentialin a regi...
We know that the poission's equation is

If a potential function  satisfied the Laplace equation  then
If means that the given potential function will exist in a charge less system. If not. then it will satisfies the poission's equation and we can calculate the charge density (ρ)
The given function are

But the boundary conditions are different in both cases. The boundary condition are along to x-axis. But one function satisfies by the Laplace's eq. and one function satisfies by the Poisson's eq. so we cannot add both solutions.
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Solving Poisson's equationfor the electrostatic potentialin a region with a constant charge densitytwo students find different answers.The reason why these different solutions are both correct is becausea)space is isotropic and hence x and y are physically equivalent.b)W e can add solutions of Laplace’s equation to bothc)The electrostatic energy is infinite for a constant charge density.d)The boundary conditions are different in the two cases.Correct answer is option 'D'. Can you explain this answer?
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Solving Poisson's equationfor the electrostatic potentialin a region with a constant charge densitytwo students find different answers.The reason why these different solutions are both correct is becausea)space is isotropic and hence x and y are physically equivalent.b)W e can add solutions of Laplace’s equation to bothc)The electrostatic energy is infinite for a constant charge density.d)The boundary conditions are different in the two cases.Correct answer is option 'D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Solving Poisson's equationfor the electrostatic potentialin a region with a constant charge densitytwo students find different answers.The reason why these different solutions are both correct is becausea)space is isotropic and hence x and y are physically equivalent.b)W e can add solutions of Laplace’s equation to bothc)The electrostatic energy is infinite for a constant charge density.d)The boundary conditions are different in the two cases.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Solving Poisson's equationfor the electrostatic potentialin a region with a constant charge densitytwo students find different answers.The reason why these different solutions are both correct is becausea)space is isotropic and hence x and y are physically equivalent.b)W e can add solutions of Laplace’s equation to bothc)The electrostatic energy is infinite for a constant charge density.d)The boundary conditions are different in the two cases.Correct answer is option 'D'. Can you explain this answer?.
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