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The output of a JK flipflop with asynchronous preset and clear inputs is ‘1’. The output can be changed to ‘0’ with one of the following conditions
  • a)
    By applying J = 0, K = 0 and using a clock
  • b)
    By applying J = 1, K = 1 and using the clock
  • c)
    By applying J = 1, K = 1 and using the clock
  • d)
    By applying a synchronous preset input
Correct answer is option 'B'. Can you explain this answer?
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The output of a JK flipflop with asynchronous preset and clear inputs ...
Preset state of JK Flip-Flop =1 With J=1 K=1 and the clock next state will be complement of the present state
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The output of a JK flipflop with asynchronous preset and clear inputs ...
The output of a JK flip-flop with asynchronous preset and clear inputs depends on the state of the inputs and the current state of the flip-flop.

If the preset input (usually denoted as "P") is set to a logic high ("1"), it will force the flip-flop's output to be high regardless of the inputs or the current state.

If the clear input (usually denoted as "CLR" or "R") is set to a logic high ("1"), it will force the flip-flop's output to be low regardless of the inputs or the current state.

If both the preset and clear inputs are set to a logic high simultaneously, it may result in an undefined state or cause the flip-flop to behave unpredictably.

If neither the preset nor clear inputs are set to a logic high, the output of the JK flip-flop with asynchronous preset and clear inputs will be determined by the J and K inputs and the current state of the flip-flop, following the truth table for a JK flip-flop.
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The output of a JK flipflop with asynchronous preset and clear inputs is ‘1’. The output can be changed to ‘0’ with one of the following conditionsa)By applying J = 0, K = 0 and using a clockb)By applying J = 1, K = 1 and using the clockc)By applying J = 1, K = 1 and using the clockd)By applying a synchronous preset inputCorrect answer is option 'B'. Can you explain this answer?
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