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The output of a J-Kflip-flop with asynchronous preset and clear inputs if ‘1 ’. The output can be changed to ‘0’ with which one of the following conditions?
- a)By applying J = 1, K= 0 and using the clock
- b)By applying a synchronous preset input
- c)By applying J = 1, K = 1 and using the clock
- d)By applying J = 0, K = 0 and using the clock
Correct answer is option 'C'. Can you explain this answer?
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The output of a J-Kflip-flop with asynchronous preset and clear inputs...
When J = 1, K = 1 and the clock, next state will be complement of the present state. Thus,
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The output of a J-Kflip-flop with asynchronous preset and clear inputs...
The output of a J-K flip-flop with asynchronous preset and clear inputs will depend on the specific inputs applied to the flip-flop.
If the asynchronous preset input (often denoted as PR or PRE) is asserted (set to a logical high or "1"), it will force the flip-flop's output to become set to a logical high or "1" regardless of the other inputs. This means that the flip-flop will ignore the J and K inputs and directly output a high signal.
If the asynchronous clear input (often denoted as CLR) is asserted (set to a logical high or "1"), it will force the flip-flop's output to become cleared to a logical low or "0" regardless of the other inputs. This means that the flip-flop will ignore the J and K inputs and directly output a low signal.
If neither the preset nor clear inputs are asserted (both set to logical lows or "0"), then the output of the flip-flop will be determined by the J and K inputs following the behavior of a regular J-K flip-flop.
In summary, the output of a J-K flip-flop with asynchronous preset and clear inputs will depend on the specific inputs applied and whether the preset or clear inputs are asserted.
If the asynchronous preset input (often denoted as PR or PRE) is asserted (set to a logical high or "1"), it will force the flip-flop's output to become set to a logical high or "1" regardless of the other inputs. This means that the flip-flop will ignore the J and K inputs and directly output a high signal.
If the asynchronous clear input (often denoted as CLR) is asserted (set to a logical high or "1"), it will force the flip-flop's output to become cleared to a logical low or "0" regardless of the other inputs. This means that the flip-flop will ignore the J and K inputs and directly output a low signal.
If neither the preset nor clear inputs are asserted (both set to logical lows or "0"), then the output of the flip-flop will be determined by the J and K inputs following the behavior of a regular J-K flip-flop.
In summary, the output of a J-K flip-flop with asynchronous preset and clear inputs will depend on the specific inputs applied and whether the preset or clear inputs are asserted.
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The output of a J-Kflip-flop with asynchronous preset and clear inputs if ‘1 ’. The output can be changed to ‘0’ with which one of the following conditions?a)By applying J = 1, K= 0 and using the clockb)By applying a synchronous preset inputc)By applying J = 1, K = 1 and using the clockd)By applying J = 0, K = 0 and using the clockCorrect answer is option 'C'. Can you explain this answer?
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