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A beam of plane-polarized light falls on a polarizer which rotates about the axis of the ray with angular velocity ω = 22 rad/sec. Find the energy (mJ) of light passing through the polarizer per one revolution if the flux of energy of the incident ray is equal to φ = 14 mω.a)4b)2c)8d)6Correct answer is option 'B'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A beam of plane-polarized light falls on a polarizer which rotates about the axis of the ray with angular velocity ω = 22 rad/sec. Find the energy (mJ) of light passing through the polarizer per one revolution if the flux of energy of the incident ray is equal to φ = 14 mω.a)4b)2c)8d)6Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A beam of plane-polarized light falls on a polarizer which rotates about the axis of the ray with angular velocity ω = 22 rad/sec. Find the energy (mJ) of light passing through the polarizer per one revolution if the flux of energy of the incident ray is equal to φ = 14 mω.a)4b)2c)8d)6Correct answer is option 'B'. Can you explain this answer?.

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