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The instantaneous position x(t) of a small block performing one dimensional damped oscillation is x(t) = Ae-rtsin (ωt +α).Here ω is the angular frequency ,r is the damping coefficient. A is the initial amplitude and α is the initial phase. Ifthe values of A and a (with n = 0, 1, 2 , ........) area)b)c)d)Correct answer is option 'B'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The instantaneous position x(t) of a small block performing one dimensional damped oscillation is x(t) = Ae-rtsin (ωt +α).Here ω is the angular frequency ,r is the damping coefficient. A is the initial amplitude and α is the initial phase. Ifthe values of A and a (with n = 0, 1, 2 , ........) area)b)c)d)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The instantaneous position x(t) of a small block performing one dimensional damped oscillation is x(t) = Ae-rtsin (ωt +α).Here ω is the angular frequency ,r is the damping coefficient. A is the initial amplitude and α is the initial phase. Ifthe values of A and a (with n = 0, 1, 2 , ........) area)b)c)d)Correct answer is option 'B'. Can you explain this answer?.

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