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The percentage profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 25% profit ?
  • a)
    Rs. 2000
  • b)
    Rs. 2200
  • c)
    Rs. 2400
  • d)
    Data inadequate
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?
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To solve this problem, let's assume the cost price of the article is Rs. x.

Given that the percentage profit earned by selling the article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280, we can write the following equation:

Profit% = Loss%

Profit% = (Selling Price - Cost Price) / Cost Price * 100
Loss% = (Cost Price - Selling Price) / Cost Price * 100

According to the given information, we have:

(Selling Price - Cost Price) / Cost Price * 100 = (Cost Price - Selling Price) / Cost Price * 100

Simplifying this equation, we get:

(Selling Price - Cost Price) = (Cost Price - Selling Price)

2 * Selling Price = 2 * Cost Price

Selling Price = Cost Price

This means that the selling price is equal to the cost price.

To find the selling price that will give a 25% profit, we need to calculate 125% of the cost price.

125% of x = 1.25x

Therefore, the article should be sold for 1.25 times the cost price to make a 25% profit.

Since the cost price is x, the selling price should be 1.25x.

To find the value of x, we can use the given information:

Rs. 1920 = 1.25x

Dividing both sides by 1.25, we get:

x = Rs. 1536

Therefore, the cost price of the article is Rs. 1536.

To make a 25% profit, the selling price should be:

1.25 * Rs. 1536 = Rs. 1920

So, the correct option is a) Rs. 2000.
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The percentage profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 25% profit ?a)Rs. 2000b)Rs. 2200c)Rs. 2400d)Data inadequatee)None of theseCorrect answer is option 'A'. Can you explain this answer?
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