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A flake of glass of index of refraction 1.5 is placed over one of the openings of a double -slit apparatus. There is a displacement of interference pattern through seven successive maxima toward the side where the flake was placed. If the wavelength of the diffracted light is λ = 600 nm, then what is the value of wavelength of flake (in nm)?
Correct answer is '8400'. Can you explain this answer?
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A flake of glass of index of refraction 1.5 is placed over one of the ...
With λ denoting the wavelength in air, the wavelength within the glass is
n where n is the refractive index of the glass. Letting t denote the thickness of the flake, the number of wavelengths contained in it (for “turning angles” 0 «1) is t/λ' = (nt)λ. In the thickness of air displaced by the flake, there would only have been t/λ wavelengths. Therefore the presence of the flake adds [(nt)/λ]-
wavelengths to the effective path of the light which passes through the flake. This causes the entire interference pattern to shift toward the side with the flake by 
fringes (i.e., one fringe per wavelength). Hence, 
n where n is the refractive index of the glass. Letting t denote the thickness of the flake, the number of wavelengths contained in it (for “turning angles” 0 «1) is t/λ' = (nt)λ. In the thickness of air displaced by the flake, there would only have been t/λ wavelengths. Therefore the presence of the flake adds [(nt)/λ]- wavelengths to the effective path of the light which passes through the flake. This causes the entire interference pattern to shift toward the side with the flake by fringes (i.e., one fringe per wavelength). Hence, Most Upvoted Answer
A flake of glass of index of refraction 1.5 is placed over one of the ...
With λ denoting the wavelength in air, the wavelength within the glass isn where n is the refractive index of the glass. Letting t denote the thickness of the flake, the number of wavelengths contained in it (for “turning angles” 0 «1) is t/λ' = (nt)λ. In the thickness of air displaced by the flake, there would only have been t/λ wavelengths. Therefore the presence of the flake adds [(nt)/λ]- wavelengths to the effective path of the light which passes through the flake. This causes the entire interference pattern to shift toward the side with the flake by fringes (i.e., one fringe per wavelength). Hence,
n where n is the refractive index of the glass. Letting t denote the thickness of the flake, the number of wavelengths contained in it (for “turning angles” 0 «1) is t/λ' = (nt)λ. In the thickness of air displaced by the flake, there would only have been t/λ wavelengths. Therefore the presence of the flake adds [(nt)/λ]- wavelengths to the effective path of the light which passes through the flake. This causes the entire interference pattern to shift toward the side with the flake by fringes (i.e., one fringe per wavelength). Hence,
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A flake of glass of index of refraction 1.5 is placed over one of the openings of a double -slit apparatus. There is a displacement of interference pattern through seven successive maxima toward the side where the flake was placed. If the wavelength of the diffracted light is λ = 600 nm, then what is the value of wavelength of flake (in nm)?Correct answer is '8400'. Can you explain this answer?
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A flake of glass of index of refraction 1.5 is placed over one of the openings of a double -slit apparatus. There is a displacement of interference pattern through seven successive maxima toward the side where the flake was placed. If the wavelength of the diffracted light is λ = 600 nm, then what is the value of wavelength of flake (in nm)?Correct answer is '8400'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A flake of glass of index of refraction 1.5 is placed over one of the openings of a double -slit apparatus. There is a displacement of interference pattern through seven successive maxima toward the side where the flake was placed. If the wavelength of the diffracted light is λ = 600 nm, then what is the value of wavelength of flake (in nm)?Correct answer is '8400'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A flake of glass of index of refraction 1.5 is placed over one of the openings of a double -slit apparatus. There is a displacement of interference pattern through seven successive maxima toward the side where the flake was placed. If the wavelength of the diffracted light is λ = 600 nm, then what is the value of wavelength of flake (in nm)?Correct answer is '8400'. Can you explain this answer?.
A flake of glass of index of refraction 1.5 is placed over one of the openings of a double -slit apparatus. There is a displacement of interference pattern through seven successive maxima toward the side where the flake was placed. If the wavelength of the diffracted light is λ = 600 nm, then what is the value of wavelength of flake (in nm)?Correct answer is '8400'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A flake of glass of index of refraction 1.5 is placed over one of the openings of a double -slit apparatus. There is a displacement of interference pattern through seven successive maxima toward the side where the flake was placed. If the wavelength of the diffracted light is λ = 600 nm, then what is the value of wavelength of flake (in nm)?Correct answer is '8400'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A flake of glass of index of refraction 1.5 is placed over one of the openings of a double -slit apparatus. There is a displacement of interference pattern through seven successive maxima toward the side where the flake was placed. If the wavelength of the diffracted light is λ = 600 nm, then what is the value of wavelength of flake (in nm)?Correct answer is '8400'. Can you explain this answer?.
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A flake of glass of index of refraction 1.5 is placed over one of the openings of a double -slit apparatus. There is a displacement of interference pattern through seven successive maxima toward the side where the flake was placed. If the wavelength of the diffracted light is λ = 600 nm, then what is the value of wavelength of flake (in nm)?Correct answer is '8400'. Can you explain this answer?, a detailed solution for A flake of glass of index of refraction 1.5 is placed over one of the openings of a double -slit apparatus. There is a displacement of interference pattern through seven successive maxima toward the side where the flake was placed. If the wavelength of the diffracted light is λ = 600 nm, then what is the value of wavelength of flake (in nm)?Correct answer is '8400'. Can you explain this answer? has been provided alongside types of A flake of glass of index of refraction 1.5 is placed over one of the openings of a double -slit apparatus. There is a displacement of interference pattern through seven successive maxima toward the side where the flake was placed. If the wavelength of the diffracted light is λ = 600 nm, then what is the value of wavelength of flake (in nm)?Correct answer is '8400'. Can you explain this answer? theory, EduRev gives you an
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