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Calculate VCE in the figure (in volts).
    Correct answer is '2.26'. Can you explain this answer?
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    Calculate VCE in the figure (in volts).Correct answer is '2.26'. Can y...
    First check to see if Rin (Base) can be neglected.

    =150 x kΩ = 150kΩ
    Since 150kΩ is more than 10 times R2. The condition  is met and Rin(base) can be neglected.

    = 6.88 V
    Then, VE = VB + VBE
    = 6.88 + 0.7
    VE = 7.58V

     lE = 2.42 mA
    From IE we can determine lc and VCE

    and VC = ICRC = 2.42 mA x 2.2kΩ
    = 5.32

    = 2.26V
    The correct answer is: 2.26
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    Calculate VCE in the figure (in volts).Correct answer is '2.26'. Can y...
    First check to see if Rin (Base) can be neglected.

    =150 x kΩ = 150kΩ
    Since 150kΩ is more than 10 times R2. The condition  is met and Rin(base) can be neglected.

    = 6.88 V
    Then, VE = VB + VBE
    = 6.88 + 0.7
    VE = 7.58V

     lE = 2.42 mA
    From IE we can determine lc and VCE

    and VC = ICRC = 2.42 mA x 2.2kΩ
    = 5.32

    = 2.26V
    The correct answer is: 2.26
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    Calculate VCE in the figure (in volts).Correct answer is '2.26'. Can you explain this answer?
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