Two circles x2 + y2 = 6 and x2 + y2 andndash; 6x + 8 = 0 are given. Then the equation of the circle through their points of intersection and the point (1, 1) is (1980)a)x2 + y2 andndash; 6x + 4 = 0b)x2 + y2 andndash; 3x + 1 = 0c)x2 + y2 andndash; 4y + 2 = 0d)none of theseCorrect answer is option 'B'. Can you explain this answer?

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Two circles x² + y² = 6 and x² + y²– 6x + 8 = 0 are given. Then the equation of the circle through their points of intersection and the point (1, 1) is (1980)

a)
x² + y² – 6x + 4 = 0
b)
x² + y²– 3x + 1 = 0
c)
x² + y² – 4y + 2 = 0
d)
none of these

Correct answer is option 'B'. Can you explain this answer?

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Two circles x2 + y2 = 6 and x2 + y2 – 6x + 8 = 0 are given. Then...

The circle through points of intersection of the two circles x² + y²– 6 = 0
and x² + y² – 6x + 8 = 0
is (x² + y² – 6) + l (x² + y² – 6x + 8) = 0
As it passes through (1, 1) (1 + 1 – 6) + l (1 + 1 – 6 + 8) = 0 ⇒

∴ The required circle is 2x² + 2y² – 6x + 2 = 0
or, x² + y² – 3x + 1 = 0

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Two circles x2 + y2 = 6 and x2 + y2 – 6x + 8 = 0 are given. Then the equation of the circle through their points of intersection and the point (1, 1) is (1980)a)x2 + y2 – 6x + 4 = 0b)x2 + y2 – 3x + 1 = 0c)x2 + y2 – 4y + 2 = 0d)none of theseCorrect answer is option 'B'. Can you explain this answer?

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