To find the equation of the plane containing the lines
The plant: containing (i) is
A ( x - a) + B ( y - b) + C ( z - c) = 0 ...(iii)
where Aa' + Bb‘ + Cc' 3 =0 ...(iv)
Further, since the plane (iii) also contains line (ii), therefore , the normal to plane (iii) is perpendicular to line (ii).
∴ Aa + Bb + Cc = 0 ...(v)
Eliminating A, B, C from equations (iii), (iv) and (v), we get the required equation of plane
This is statement (b). The statements (a) and (c) can be deduced from this by simple propert ies of determinants. Thus (a), (b|, (c) are correct.