The three planes are

Denote the determinants as follows:

Note that Δ is th e coefficients of x, y and z . Δ
1, Δ
2 and Δ
3, are obtained from Δ by replacing its first column, 2nd column and 3rd column by d
1, d
2 and d
3, respectively.
Also note that if the three planes are to intersect in a line, then no two of them are parallel. Under this case, the line of intersection of any two planes will lie on the third plane. Now the line of intersection of (i) and (ii) is given by

Since line (iv) lies on plane (iii), therefore is perpendicuar to the normal to the plane (iii)


Also since line (iv) lies on plane (iii), therefore the coordinates of any point on the line will satisfy the equation of plane (iii), since



Thus (A) and (R) are the required conditions for the three planes to have a common line of intersection.
In a similar way, it can he shown that Δ = 0 and Δ
1 = 0 or Δ = 0 and Δ
2 = 0 are also the required conditions.
∴ (b), (c), (d) are correct.
Remark: To prove that three planes intersect in a line, verify that Δ = 0 and any one: of Δ
1,Δ
2 and Δ
3
becomes zero.