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On a system using round-robin scheduling let 's' represent the time needed to perform a process switch, 'q' represents the round-robin time quantum, and 'r' represents the average time a process runs before blocking on I/O. The CPU efficiency when s = q < r is:a)r/(r+s)b)q/(q+s)c)1/2d)0Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared
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the GATE exam syllabus. Information about On a system using round-robin scheduling let 's' represent the time needed to perform a process switch, 'q' represents the round-robin time quantum, and 'r' represents the average time a process runs before blocking on I/O. The CPU efficiency when s = q < r is:a)r/(r+s)b)q/(q+s)c)1/2d)0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam.
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On a system using round-robin scheduling let 's' represent the time needed to perform a process switch, 'q' represents the round-robin time quantum, and 'r' represents the average time a process runs before blocking on I/O. The CPU efficiency when s = q < r is:a)r/(r+s)b)q/(q+s)c)1/2d)0Correct answer is option 'C'. Can you explain this answer?, a detailed solution for On a system using round-robin scheduling let 's' represent the time needed to perform a process switch, 'q' represents the round-robin time quantum, and 'r' represents the average time a process runs before blocking on I/O. The CPU efficiency when s = q < r is:a)r/(r+s)b)q/(q+s)c)1/2d)0Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of On a system using round-robin scheduling let 's' represent the time needed to perform a process switch, 'q' represents the round-robin time quantum, and 'r' represents the average time a process runs before blocking on I/O. The CPU efficiency when s = q < r is:a)r/(r+s)b)q/(q+s)c)1/2d)0Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice On a system using round-robin scheduling let 's' represent the time needed to perform a process switch, 'q' represents the round-robin time quantum, and 'r' represents the average time a process runs before blocking on I/O. The CPU efficiency when s = q < r is:a)r/(r+s)b)q/(q+s)c)1/2d)0Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice GATE tests.