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On a system using round-robin scheduling let 's' represent the time needed to perform a process switch, 'q' represents the round-robin time quantum, and 'r' represents the average time a process runs before blocking on I/O. The CPU efficiency when s = q < r is:
  • a)
    r/(r+s)
  • b)
    q/(q+s)
  • c)
    1/2
  • d)
    0
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
On a system using round-robin scheduling let 's' represent the...
‘r’ is the average time a process runs before I/O block and ‘s’ is the time needed for switch. 'q' represents the round-robin time quantum. The efficiency of the CPU when s < r and q < r. = r/(r/q)*s+r = q/(q+s) Here s = q. Hence efficiency is ½.
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Most Upvoted Answer
On a system using round-robin scheduling let 's' represent the...
When s = q, it means that the time needed to perform a process switch is equal to the round-robin time quantum. In this case, the CPU efficiency can be calculated as:

CPU efficiency = (q / (q + r)) * 100%

Here, q is the time quantum and r is the average time a process runs before blocking on I/O.

If s = q, then the process switch time is equal to the time quantum. This means that each process will run for exactly one time quantum before being switched out. Therefore, the CPU efficiency can be calculated using the formula above.
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On a system using round-robin scheduling let 's' represent the time needed to perform a process switch, 'q' represents the round-robin time quantum, and 'r' represents the average time a process runs before blocking on I/O. The CPU efficiency when s = q < r is:a)r/(r+s)b)q/(q+s)c)1/2d)0Correct answer is option 'C'. Can you explain this answer?
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On a system using round-robin scheduling let 's' represent the time needed to perform a process switch, 'q' represents the round-robin time quantum, and 'r' represents the average time a process runs before blocking on I/O. The CPU efficiency when s = q < r is:a)r/(r+s)b)q/(q+s)c)1/2d)0Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about On a system using round-robin scheduling let 's' represent the time needed to perform a process switch, 'q' represents the round-robin time quantum, and 'r' represents the average time a process runs before blocking on I/O. The CPU efficiency when s = q < r is:a)r/(r+s)b)q/(q+s)c)1/2d)0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On a system using round-robin scheduling let 's' represent the time needed to perform a process switch, 'q' represents the round-robin time quantum, and 'r' represents the average time a process runs before blocking on I/O. The CPU efficiency when s = q < r is:a)r/(r+s)b)q/(q+s)c)1/2d)0Correct answer is option 'C'. Can you explain this answer?.
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