Consider a 5-bit right shift register each shifting data to the right ...
In the right shift register always MSB is the last bit so here Q4 is the MSB.
The table showing the transition is-
Therefore the no of clock pulse is 13.
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Consider a 5-bit right shift register each shifting data to the right ...
Problem: Consider a 5-bit right shift register with a serial input A derived using NAND gates. If the initial content of the counter is 10001 at Q0Q1Q2Q3Q4, after how many clock pulses will the circuit be back to the initial state?
Solution:
Step 1: Understanding the given shift register and serial input
The given shift register is a 5-bit right shift register, meaning that every clock pulse will shift the data one bit to the right. The serial input A is derived using NAND gates, which means that it will be 1 only when both inputs are 0.
Step 2: Determining the output sequence of the shift register
The initial content of the shift register is 10001. The first clock pulse will shift the data one bit to the right, resulting in 01000. The second clock pulse will shift the data again, resulting in 00100. This process will continue for 11 clock pulses until the output sequence becomes 00001. The next clock pulse will shift the data one more time, resulting in 00000. The next clock pulse will result in the output sequence becoming 10000, which is the initial state of the shift register. Therefore, the circuit will be back to the initial state after 13 clock pulses.
Step 3: Verifying the answer
We can verify the answer by simulating the shift register using a digital logic simulator. The simulation will show that the circuit is back to the initial state after 13 clock pulses.