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A certain steel has proportionality limit of 300 N/mm2 in simple tension. It is subjected to principal stress of 120 N/mm2 (tensile), 60 N/mm2 (tensile) and 30 N/mm2 (compressive). The factor of safety according to maximum shear stress theory is
  • a)
    1.50
  • b)
    1.75
  • c)
    1.80
  • d)
    2.00
Correct answer is option 'D'. Can you explain this answer?
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A certain steel has proportionality limit of 300 N/mm2 in simple tensi...
Proportionality limit shear stress

Maximum shear stress

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A certain steel has proportionality limit of 300 N/mm2 in simple tensi...
Given Data:
Proportionality limit (σp) = 300 N/mm²
Principal stress (σ1) = 120 N/mm² (Tensile)
Principal stress (σ2) = 60 N/mm² (Tensile)
Principal stress (σ3) = 30 N/mm² (Compressive)

Formula:
Factor of Safety (FoS) according to Maximum Shear Stress Theory = σp / (σ1 - σ3)

Calculation:
σ1 - σ3 = 120 - (-30) = 150 N/mm²
FoS = σp / (σ1 - σ3)
FoS = 300 / 150
FoS = 2

Therefore, the factor of safety according to maximum shear stress theory is 2 or 2.00.
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A certain steel has proportionality limit of 300 N/mm2 in simple tension. It is subjected to principal stress of 120 N/mm2 (tensile), 60 N/mm2 (tensile) and 30 N/mm2 (compressive). The factor of safety according to maximum shear stress theory isa)1.50b)1.75c)1.80d)2.00Correct answer is option 'D'. Can you explain this answer?
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A certain steel has proportionality limit of 300 N/mm2 in simple tension. It is subjected to principal stress of 120 N/mm2 (tensile), 60 N/mm2 (tensile) and 30 N/mm2 (compressive). The factor of safety according to maximum shear stress theory isa)1.50b)1.75c)1.80d)2.00Correct answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A certain steel has proportionality limit of 300 N/mm2 in simple tension. It is subjected to principal stress of 120 N/mm2 (tensile), 60 N/mm2 (tensile) and 30 N/mm2 (compressive). The factor of safety according to maximum shear stress theory isa)1.50b)1.75c)1.80d)2.00Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A certain steel has proportionality limit of 300 N/mm2 in simple tension. It is subjected to principal stress of 120 N/mm2 (tensile), 60 N/mm2 (tensile) and 30 N/mm2 (compressive). The factor of safety according to maximum shear stress theory isa)1.50b)1.75c)1.80d)2.00Correct answer is option 'D'. Can you explain this answer?.
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