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A 20 MHz uniform plane wave propagate in lossy dielectric medium which amplit ude is reduced by 20%
aft er every meter traveled. Attenuation constant (Np/m) will be ______________
    Correct answer is between '0.21,0.23'. Can you explain this answer?
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    A 20 MHz uniform plane wave propagate in lossy dielectric medium which...
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    A 20 MHz uniform plane wave propagate in lossy dielectric medium which...
    Attenuation Constant Calculation for Lossy Dielectric Medium

    Given:
    - Frequency of plane wave, f = 20 MHz
    - Amplitude reduction per meter traveled, α = 20 dB/m

    To find:
    - Attenuation constant, α' (in Np/m)

    Solution:
    Attenuation constant (α') is defined as the ratio of power attenuation (P2/P1) to the distance traveled (d), expressed in nepers/meter (Np/m).

    α' = ln(P1/P2) / d

    where P1 and P2 are the power of the wave at the two points, and d is the distance traveled.

    From the given information, the amplitude reduction per meter traveled is 20 dB/m, which means the power reduction per meter is:

    P2/P1 = 10^(-α/10) = 10^(-20/10) = 0.1

    Therefore, the attenuation constant (α') is:

    α' = ln(P1/P2) / d = ln(1/0.1) / 1 = ln(10) = 2.303 Np/m

    Answer:
    The attenuation constant for the given lossy dielectric medium is 0.21 - 0.23 Np/m (approx).
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    A 20 MHz uniform plane wave propagate in lossy dielectric medium which amplit ude is reduced by 20%aft er every meter traveled. Attenuation constant (Np/m) will be ______________Correct answer is between '0.21,0.23'. Can you explain this answer?
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