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A 100 m tape is suspended between the ends under a pull of 200 N. The weight of the tape is 30 N. The correction for sag and correct distance between the tape ends is
  • a)
    0.056 m; 99.944 m
  • b)
    0.094 m; 99.906 m
  • c)
    0.094 m; 100.094 m 
  • d)
    0.056.m; 100.056 m 
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A 100 m tape is suspended between the ends under a pullof 200 N. The w...


Correct distance = 100 - 0.094 = 99.906 m
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Most Upvoted Answer
A 100 m tape is suspended between the ends under a pullof 200 N. The w...
Given data:
Length of tape (L) = 100 m
Pull on tape (P) = 200 N
Weight of tape per unit length (w) = 30 N/m

To find:
Correction for sag (C) and Correct distance between the tape ends (D)

Calculation:
Let us assume that the tape is hanging in the form of a parabola. The sag correction can be calculated using the formula:

C = (w/2P) x L^2

Substituting the given values, we get:

C = (30/(2x200)) x (100)^2
C = 0.5625 m
C = 0.056 m (approx)

Therefore, the sag correction is 0.056 m.

The actual length between the tape ends can be calculated using the formula:

D = L + 2C

Substituting the values, we get:

D = 100 + 2(0.056)
D = 100.112 m
D = 100.094 m (approx)

Therefore, the correct distance between the tape ends is 100.094 m.

Hence, the correct answer is option B - 0.094 m; 99.906 m.
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A 100 m tape is suspended between the ends under a pullof 200 N. The weight of the tape is 30 N. The correction for sag and correct distance between the tape ends isa)0.056 m; 99.944 mb)0.094 m; 99.906 mc)0.094 m; 100.094 md)0.056.m; 100.056 mCorrect answer is option 'B'. Can you explain this answer?
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A 100 m tape is suspended between the ends under a pullof 200 N. The weight of the tape is 30 N. The correction for sag and correct distance between the tape ends isa)0.056 m; 99.944 mb)0.094 m; 99.906 mc)0.094 m; 100.094 md)0.056.m; 100.056 mCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A 100 m tape is suspended between the ends under a pullof 200 N. The weight of the tape is 30 N. The correction for sag and correct distance between the tape ends isa)0.056 m; 99.944 mb)0.094 m; 99.906 mc)0.094 m; 100.094 md)0.056.m; 100.056 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 100 m tape is suspended between the ends under a pullof 200 N. The weight of the tape is 30 N. The correction for sag and correct distance between the tape ends isa)0.056 m; 99.944 mb)0.094 m; 99.906 mc)0.094 m; 100.094 md)0.056.m; 100.056 mCorrect answer is option 'B'. Can you explain this answer?.
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