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The sag correction in a tape of length 20 m and weight 15 kg/m suspended at its ends is ________ m. Take a pull equal to 45 kg. (Answer up to two decimal places)
Correct answer is '37.04'. Can you explain this answer?
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The sag correction in a tape of length 20 m and weight 15 kg/m suspen...
Sag Correction in a Tape
To determine the sag correction in a tape, we need to consider the weight of the tape itself and the tension applied to it. The sag correction accounts for the deviation in the tape caused by its own weight and the pull applied to it.
Given:
- Length of the tape (L) = 20 m
- Weight of the tape (W) = 15 kg/m
- Pull applied (P) = 45 kg
Calculating the Sag Correction:
The sag correction can be determined using the formula:
Sag Correction (S) = (P^2 * L^2) / (8 * W)
Substituting the given values:
S = (45^2 * 20^2) / (8 * 15)
Simplifying the equation:
S = (2025 * 400) / 120
S = 810000 / 120
S = 6750
Converting the sag correction to meters:
S = 6750 / 1000
S = 6.75 m
Correcting the Sag:
To correct for the sag in the tape, we need to subtract the sag correction from the measured length of the tape.
Corrected Length = Measured Length - Sag Correction
Corrected Length = 20 - 6.75
Corrected Length = 13.25 m
Therefore, the correct answer for the sag correction in this case is 6.75 m.
To determine the sag correction in a tape, we need to consider the weight of the tape itself and the tension applied to it. The sag correction accounts for the deviation in the tape caused by its own weight and the pull applied to it.
Given:
- Length of the tape (L) = 20 m
- Weight of the tape (W) = 15 kg/m
- Pull applied (P) = 45 kg
Calculating the Sag Correction:
The sag correction can be determined using the formula:
Sag Correction (S) = (P^2 * L^2) / (8 * W)
Substituting the given values:
S = (45^2 * 20^2) / (8 * 15)
Simplifying the equation:
S = (2025 * 400) / 120
S = 810000 / 120
S = 6750
Converting the sag correction to meters:
S = 6750 / 1000
S = 6.75 m
Correcting the Sag:
To correct for the sag in the tape, we need to subtract the sag correction from the measured length of the tape.
Corrected Length = Measured Length - Sag Correction
Corrected Length = 20 - 6.75
Corrected Length = 13.25 m
Therefore, the correct answer for the sag correction in this case is 6.75 m.
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The sag correction in a tape of length 20 m and weight 15 kg/m suspen...
Given: l = 20 m, W = 15 kg/m and P = 45 kg
Sag correction is
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The sag correction in a tape of length 20 m and weight 15 kg/m suspended at its ends is ________ m. Take a pull equal to 45 kg. (Answer up to two decimal places)Correct answer is '37.04'. Can you explain this answer?
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The sag correction in a tape of length 20 m and weight 15 kg/m suspended at its ends is ________ m. Take a pull equal to 45 kg. (Answer up to two decimal places)Correct answer is '37.04'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The sag correction in a tape of length 20 m and weight 15 kg/m suspended at its ends is ________ m. Take a pull equal to 45 kg. (Answer up to two decimal places)Correct answer is '37.04'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sag correction in a tape of length 20 m and weight 15 kg/m suspended at its ends is ________ m. Take a pull equal to 45 kg. (Answer up to two decimal places)Correct answer is '37.04'. Can you explain this answer?.
The sag correction in a tape of length 20 m and weight 15 kg/m suspended at its ends is ________ m. Take a pull equal to 45 kg. (Answer up to two decimal places)Correct answer is '37.04'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The sag correction in a tape of length 20 m and weight 15 kg/m suspended at its ends is ________ m. Take a pull equal to 45 kg. (Answer up to two decimal places)Correct answer is '37.04'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sag correction in a tape of length 20 m and weight 15 kg/m suspended at its ends is ________ m. Take a pull equal to 45 kg. (Answer up to two decimal places)Correct answer is '37.04'. Can you explain this answer?.
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