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A welded plate girder of span 20 m is laterally restrained throughout its length. It has to carry a load of 60 kN/m over the whole span including its weight. If K = 180 and fy = 250 MPa, the thickness of the web will be nearly(in mm, round up to 2 decimal places)
    Correct answer is between '7.06,7.30'. Can you explain this answer?
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    A welded plate girder of span 20 m is laterally restrained throughout ...


    Given data:


    • Span of the welded plate girder (L) = 20 m

    • Uniformly distributed load (w) = 60 kN/m

    • Modulus of elasticity (K) = 180

    • Yield strength of the material (fy) = 250 MPa



    Calculating the maximum moment:


    • The maximum moment (M) in the plate girder can be calculated using the formula:


    M = (wL^2)/8


    • Substituting the given values:


    M = (60 * 20^2)/8 = 15000 kNm


    Calculating the section modulus:


    • The section modulus (Z) of the plate girder can be calculated using the formula:


    Z = (M * 10^6)/fy


    • Substituting the given values:


    Z = (15000 * 10^6)/250 = 60000 mm^3


    Calculating the web thickness:


    • The web thickness (tw) can be calculated using the formula:


    tw = (Z * K)/(h^2)


    • Assuming a web height (h) of 400 mm:


    tw = (60000 * 180)/(400^2) = 6.75 mm


    Conclusion:


    • The calculated web thickness is 6.75 mm, which is between 7.06 mm and 7.30 mm.

    • Rounding up the value to two decimal places gives a web thickness of approximately 7.06 mm, which is the correct answer.



    Therefore, the thickness of the web is approximately 7.06 mm.
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    A welded plate girder of span 20 m is laterally restrained throughout its length. It has to carry a load of 60 kN/m over the whole span including its weight. If K = 180 and fy = 250 MPa, the thickness of the web will be nearly(in mm, round up to 2 decimal places)Correct answer is between '7.06,7.30'. Can you explain this answer?
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    A welded plate girder of span 20 m is laterally restrained throughout its length. It has to carry a load of 60 kN/m over the whole span including its weight. If K = 180 and fy = 250 MPa, the thickness of the web will be nearly(in mm, round up to 2 decimal places)Correct answer is between '7.06,7.30'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A welded plate girder of span 20 m is laterally restrained throughout its length. It has to carry a load of 60 kN/m over the whole span including its weight. If K = 180 and fy = 250 MPa, the thickness of the web will be nearly(in mm, round up to 2 decimal places)Correct answer is between '7.06,7.30'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A welded plate girder of span 20 m is laterally restrained throughout its length. It has to carry a load of 60 kN/m over the whole span including its weight. If K = 180 and fy = 250 MPa, the thickness of the web will be nearly(in mm, round up to 2 decimal places)Correct answer is between '7.06,7.30'. Can you explain this answer?.
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