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Calculate the surface area of a catalyst that adsorbs 103 cm3 of nitrogen reduced to STP per gram in order to form the monolayer. The effective area occupied by N2 molecule on the surface is 1.62 × 10–15 cm2.
Correct answer is '43416000'. Can you explain this answer?
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To solve this problem, we need to use the equation for monolayer coverage:
θ = (V/M) / A
where:
θ = monolayer coverage (in molecules/atom)
V = volume of gas adsorbed (in cm3/g)
M = molecular weight of gas
A = surface area of catalyst (in cm2/g)
Since we are given that the catalyst adsorbs 103 cm3 of nitrogen per gram, we can plug in these values:
θ = (103/28) / A
where the molecular weight of nitrogen is 28 g/mol. Solving for A, we get:
A = (103/28) / θ
To find θ, we need to convert the effective area occupied by a nitrogen molecule on the surface into square centimeters. Since the question gives us this value as 1.62 Å2, we need to convert Å2 into cm2:
1 Å = 10^-8 cm
1 Å2 = 10^-16 cm2
Therefore, 1.62 Å2 = 1.62 x 10^-16 cm2. We can now use this value to calculate θ:
θ = A / (1.62 x 10^-16)
Substituting this into our equation for A, we get:
A = (103/28) / (A / (1.62 x 10^-16))
Simplifying this equation, we get:
A^2 = (103/28) / (1.62 x 10^-16)
A = √[(103/28) / (1.62 x 10^-16)]
A = 7.63 x 10^11 cm2/g
Therefore, the surface area of the catalyst that adsorbs 103 cm3 of nitrogen reduced to STP per gram in order to form the monolayer is approximately 7.63 x 10^11 cm2/g.
θ = (V/M) / A
where:
θ = monolayer coverage (in molecules/atom)
V = volume of gas adsorbed (in cm3/g)
M = molecular weight of gas
A = surface area of catalyst (in cm2/g)
Since we are given that the catalyst adsorbs 103 cm3 of nitrogen per gram, we can plug in these values:
θ = (103/28) / A
where the molecular weight of nitrogen is 28 g/mol. Solving for A, we get:
A = (103/28) / θ
To find θ, we need to convert the effective area occupied by a nitrogen molecule on the surface into square centimeters. Since the question gives us this value as 1.62 Å2, we need to convert Å2 into cm2:
1 Å = 10^-8 cm
1 Å2 = 10^-16 cm2
Therefore, 1.62 Å2 = 1.62 x 10^-16 cm2. We can now use this value to calculate θ:
θ = A / (1.62 x 10^-16)
Substituting this into our equation for A, we get:
A = (103/28) / (A / (1.62 x 10^-16))
Simplifying this equation, we get:
A^2 = (103/28) / (1.62 x 10^-16)
A = √[(103/28) / (1.62 x 10^-16)]
A = 7.63 x 10^11 cm2/g
Therefore, the surface area of the catalyst that adsorbs 103 cm3 of nitrogen reduced to STP per gram in order to form the monolayer is approximately 7.63 x 10^11 cm2/g.
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Calculate the surface area of a catalyst that adsorbs 103 cm3 of nitrogen reduced to STP per gram in order to form the monolayer. The effective area occupied by N2 molecule on the surface is 1.62 × 10–15 cm2.Correct answer is '43416000'. Can you explain this answer?
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Calculate the surface area of a catalyst that adsorbs 103 cm3 of nitrogen reduced to STP per gram in order to form the monolayer. The effective area occupied by N2 molecule on the surface is 1.62 × 10–15 cm2.Correct answer is '43416000'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Calculate the surface area of a catalyst that adsorbs 103 cm3 of nitrogen reduced to STP per gram in order to form the monolayer. The effective area occupied by N2 molecule on the surface is 1.62 × 10–15 cm2.Correct answer is '43416000'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the surface area of a catalyst that adsorbs 103 cm3 of nitrogen reduced to STP per gram in order to form the monolayer. The effective area occupied by N2 molecule on the surface is 1.62 × 10–15 cm2.Correct answer is '43416000'. Can you explain this answer?.
Calculate the surface area of a catalyst that adsorbs 103 cm3 of nitrogen reduced to STP per gram in order to form the monolayer. The effective area occupied by N2 molecule on the surface is 1.62 × 10–15 cm2.Correct answer is '43416000'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Calculate the surface area of a catalyst that adsorbs 103 cm3 of nitrogen reduced to STP per gram in order to form the monolayer. The effective area occupied by N2 molecule on the surface is 1.62 × 10–15 cm2.Correct answer is '43416000'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the surface area of a catalyst that adsorbs 103 cm3 of nitrogen reduced to STP per gram in order to form the monolayer. The effective area occupied by N2 molecule on the surface is 1.62 × 10–15 cm2.Correct answer is '43416000'. Can you explain this answer?.
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