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An inverting amplifier using the 741C must have a fiat response upto 40 kHz. The gain of the amplifier is 10 and slew rate is 0.5 V/μS. The maximum peak-to-peak input signal that can be applied without distorting the output is approximately equal to
- a)0.32 V
- b)0.60 V
- c)0.40 V
- d)0.28 V
Correct answer is option 'C'. Can you explain this answer?
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An inverting amplifier using the 741C must have a fiat response upto 4...
Μs. The input signal frequency is 10 kHz and peak-to-peak voltage is 0.1 V. Determine if the amplifier can accurately amplify this input signal without distortion.
To determine if the amplifier can accurately amplify the input signal without distortion, we need to consider the bandwidth and slew rate limitations of the amplifier.
First, let's calculate the maximum output voltage swing that the amplifier can handle without distortion. The slew rate (SR) is the maximum rate of change of the output voltage and is given as 0.5 V/µs. The maximum change in output voltage (ΔV) can be calculated using the formula:
ΔV = SR * Δt
Where Δt is the time duration for which the maximum rate of change is sustained. In this case, the input signal frequency is 10 kHz, so the time period (T) is 1/10 kHz = 100 µs. Therefore, the time duration (Δt) can be taken as half the time period, i.e., 50 µs.
ΔV = 0.5 V/µs * 50 µs = 25 V
So, the maximum output voltage swing that the amplifier can handle without distortion is 25 V.
Next, let's calculate the required bandwidth of the amplifier. The gain-bandwidth product (GBP) is a characteristic of the amplifier and is given as 40 kHz in this case. The bandwidth (BW) can be calculated using the formula:
BW = GBP / Gain
Where Gain is the desired gain of the amplifier, which is given as 10.
BW = 40 kHz / 10 = 4 kHz
So, the required bandwidth of the amplifier is 4 kHz.
Based on the given information, we can conclude that the amplifier can accurately amplify the input signal without distortion. The input signal frequency of 10 kHz is within the required bandwidth of 4 kHz, and the peak-to-peak voltage of 0.1 V is well below the maximum output voltage swing of 25 V.
To determine if the amplifier can accurately amplify the input signal without distortion, we need to consider the bandwidth and slew rate limitations of the amplifier.
First, let's calculate the maximum output voltage swing that the amplifier can handle without distortion. The slew rate (SR) is the maximum rate of change of the output voltage and is given as 0.5 V/µs. The maximum change in output voltage (ΔV) can be calculated using the formula:
ΔV = SR * Δt
Where Δt is the time duration for which the maximum rate of change is sustained. In this case, the input signal frequency is 10 kHz, so the time period (T) is 1/10 kHz = 100 µs. Therefore, the time duration (Δt) can be taken as half the time period, i.e., 50 µs.
ΔV = 0.5 V/µs * 50 µs = 25 V
So, the maximum output voltage swing that the amplifier can handle without distortion is 25 V.
Next, let's calculate the required bandwidth of the amplifier. The gain-bandwidth product (GBP) is a characteristic of the amplifier and is given as 40 kHz in this case. The bandwidth (BW) can be calculated using the formula:
BW = GBP / Gain
Where Gain is the desired gain of the amplifier, which is given as 10.
BW = 40 kHz / 10 = 4 kHz
So, the required bandwidth of the amplifier is 4 kHz.
Based on the given information, we can conclude that the amplifier can accurately amplify the input signal without distortion. The input signal frequency of 10 kHz is within the required bandwidth of 4 kHz, and the peak-to-peak voltage of 0.1 V is well below the maximum output voltage swing of 25 V.
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An inverting amplifier using the 741C must have a fiat response upto 40 kHz. The gain of the amplifier is 10 and slew rate is 0.5 V/μS. The maximum peak-to-peak input signal that can be applied without distorting the output is approximately equal toa)0.32 Vb)0.60 Vc)0.40 Vd)0.28 VCorrect answer is option 'C'. Can you explain this answer?
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An inverting amplifier using the 741C must have a fiat response upto 40 kHz. The gain of the amplifier is 10 and slew rate is 0.5 V/μS. The maximum peak-to-peak input signal that can be applied without distorting the output is approximately equal toa)0.32 Vb)0.60 Vc)0.40 Vd)0.28 VCorrect answer is option 'C'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about An inverting amplifier using the 741C must have a fiat response upto 40 kHz. The gain of the amplifier is 10 and slew rate is 0.5 V/μS. The maximum peak-to-peak input signal that can be applied without distorting the output is approximately equal toa)0.32 Vb)0.60 Vc)0.40 Vd)0.28 VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An inverting amplifier using the 741C must have a fiat response upto 40 kHz. The gain of the amplifier is 10 and slew rate is 0.5 V/μS. The maximum peak-to-peak input signal that can be applied without distorting the output is approximately equal toa)0.32 Vb)0.60 Vc)0.40 Vd)0.28 VCorrect answer is option 'C'. Can you explain this answer?.
An inverting amplifier using the 741C must have a fiat response upto 40 kHz. The gain of the amplifier is 10 and slew rate is 0.5 V/μS. The maximum peak-to-peak input signal that can be applied without distorting the output is approximately equal toa)0.32 Vb)0.60 Vc)0.40 Vd)0.28 VCorrect answer is option 'C'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about An inverting amplifier using the 741C must have a fiat response upto 40 kHz. The gain of the amplifier is 10 and slew rate is 0.5 V/μS. The maximum peak-to-peak input signal that can be applied without distorting the output is approximately equal toa)0.32 Vb)0.60 Vc)0.40 Vd)0.28 VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An inverting amplifier using the 741C must have a fiat response upto 40 kHz. The gain of the amplifier is 10 and slew rate is 0.5 V/μS. The maximum peak-to-peak input signal that can be applied without distorting the output is approximately equal toa)0.32 Vb)0.60 Vc)0.40 Vd)0.28 VCorrect answer is option 'C'. Can you explain this answer?.
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An inverting amplifier using the 741C must have a fiat response upto 40 kHz. The gain of the amplifier is 10 and slew rate is 0.5 V/μS. The maximum peak-to-peak input signal that can be applied without distorting the output is approximately equal toa)0.32 Vb)0.60 Vc)0.40 Vd)0.28 VCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for An inverting amplifier using the 741C must have a fiat response upto 40 kHz. The gain of the amplifier is 10 and slew rate is 0.5 V/μS. The maximum peak-to-peak input signal that can be applied without distorting the output is approximately equal toa)0.32 Vb)0.60 Vc)0.40 Vd)0.28 VCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of An inverting amplifier using the 741C must have a fiat response upto 40 kHz. The gain of the amplifier is 10 and slew rate is 0.5 V/μS. The maximum peak-to-peak input signal that can be applied without distorting the output is approximately equal toa)0.32 Vb)0.60 Vc)0.40 Vd)0.28 VCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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