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A bearing has a specific dynamic radial capacity of 40 kN. What equivalent radial load P can the bearing carry at 400 rpm, if the desired life H is 5000 hours for 90% of the bearings?
  • a)
    8.11 kN
  • b)
    6 kN
  • c)
    6.8 kN
  • d)
    9.11 kN
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A bearing has a specific dynamic radial capacity of 40 kN. What equiva...
Life in revolutions = (5000 x 60) min x 400 rev/ min = 120 x 106 rev
Life in millions of revoutions = (C/P)3
View all questions of this test
Most Upvoted Answer
A bearing has a specific dynamic radial capacity of 40 kN. What equiva...
Given data:
Dynamic radial capacity (C) = 40 kN
Rotational speed (N) = 400 rpm
Desired life (H) = 5000 hours
Probability of survival (P) = 90%

To find:
Equivalent radial load (P)

Formula used:
P = (C/P) x (60N/10^6)^1/2 x (H/1000)^-1/2

Calculation:
Substituting the given values in the formula, we get:
P = (40/0.9) x (60 x 400/10^6)^1/2 x (5000/1000)^-1/2
P = 8.11 kN

Therefore, the equivalent radial load that the bearing can carry at 400 rpm to achieve a desired life of 5000 hours for 90% of the bearings is 8.11 kN.
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