A taper roller bearing has a dynamic load capacity of 26 kN. The desi...
Given,C = 26 kN, L10h = 8000h, N = 300 rpm
144 million revolutions
Since, bearing is subjected to purely radial load,
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A taper roller bearing has a dynamic load capacity of 26 kN. The desi...
Given data:
Dynamic load capacity = 26 kN
Desired life for 90% of bearings = 8000 hours
Speed = 300 rpm
To find: Equivalent radial load that the bearing can carry in N
Formula used:
Equivalent radial load = (P/C)^(1/3) * Fr
Where,
P = Dynamic load capacity
C = Basic dynamic load rating
Fr = Equivalent radial load
Basic dynamic load rating (C) can be calculated using the formula:
C = (P/K)^(1/3)
Where,
K = Life factor
Calculation:
Given,
Dynamic load capacity (P) = 26 kN
Desired life for 90% of bearings = 8000 hours
Speed = 300 rpm
From the bearing life equation,
L10h = (C/P)^3 * (10/3) * (60/n)
Where,
L10h = Rated life of the bearing in hours
n = Speed in rpm
For 90% reliability, we have:
L10h = (C/P)^3 * (10/3) * (60/n) = 8000
Substituting the given values, we get:
C = 29.5 kN
K = P/C = 0.88
Now, substituting the values of P, C, and K in the formula for equivalent radial load, we get:
Equivalent radial load = (P/C)^(1/3) * Fr
Fr = Equivalent radial load / (P/C)^(1/3)
Fr = 5854 N (approx)
Therefore, the equivalent radial load that the bearing can carry is 5854 N (approx). Hence, option (c) is the correct answer.
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