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For an astabie multivibrator shown below,R1= 116 KΩ, R2= 100 KΩ, and± Vsat = ± 14 V.The time constant of the circuit to produce an output of frequency 1 kHz will bea)1 msb)0.5 msc)1.5 msd)0.75 msCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about For an astabie multivibrator shown below,R1= 116 KΩ, R2= 100 KΩ, and± Vsat = ± 14 V.The time constant of the circuit to produce an output of frequency 1 kHz will bea)1 msb)0.5 msc)1.5 msd)0.75 msCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For an astabie multivibrator shown below,R1= 116 KΩ, R2= 100 KΩ, and± Vsat = ± 14 V.The time constant of the circuit to produce an output of frequency 1 kHz will bea)1 msb)0.5 msc)1.5 msd)0.75 msCorrect answer is option 'B'. Can you explain this answer?.

Solutions for For an astabie multivibrator shown below,R1= 116 KΩ, R2= 100 KΩ, and± Vsat = ± 14 V.The time constant of the circuit to produce an output of frequency 1 kHz will bea)1 msb)0.5 msc)1.5 msd)0.75 msCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE). Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.

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