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Using a sequential implementation, it takes a total of 320 ns for each instruction, 300 ns for the combinational logic to complete, and 20 ns to store the result (in a register). This means that a throughput will be about 3.12 millions instructions/second. Assuming you switch to a 3 stage pipeline by splitting thecombinational logic into three equal parts and all registers take 20 ns to store resultsBy assuming the pipeline never starts, what will the improvement in throughput be?a)2 Instruction / 300 nsb)2 Instruction / 360 nsc)3 Instruction / 360 nsd)3 Instruction / 300 nsCorrect answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Using a sequential implementation, it takes a total of 320 ns for each instruction, 300 ns for the combinational logic to complete, and 20 ns to store the result (in a register). This means that a throughput will be about 3.12 millions instructions/second. Assuming you switch to a 3 stage pipeline by splitting thecombinational logic into three equal parts and all registers take 20 ns to store resultsBy assuming the pipeline never starts, what will the improvement in throughput be?a)2 Instruction / 300 nsb)2 Instruction / 360 nsc)3 Instruction / 360 nsd)3 Instruction / 300 nsCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Using a sequential implementation, it takes a total of 320 ns for each instruction, 300 ns for the combinational logic to complete, and 20 ns to store the result (in a register). This means that a throughput will be about 3.12 millions instructions/second. Assuming you switch to a 3 stage pipeline by splitting thecombinational logic into three equal parts and all registers take 20 ns to store resultsBy assuming the pipeline never starts, what will the improvement in throughput be?a)2 Instruction / 300 nsb)2 Instruction / 360 nsc)3 Instruction / 360 nsd)3 Instruction / 300 nsCorrect answer is option 'C'. Can you explain this answer?.

Solutions for Using a sequential implementation, it takes a total of 320 ns for each instruction, 300 ns for the combinational logic to complete, and 20 ns to store the result (in a register). This means that a throughput will be about 3.12 millions instructions/second. Assuming you switch to a 3 stage pipeline by splitting thecombinational logic into three equal parts and all registers take 20 ns to store resultsBy assuming the pipeline never starts, what will the improvement in throughput be?a)2 Instruction / 300 nsb)2 Instruction / 360 nsc)3 Instruction / 360 nsd)3 Instruction / 300 nsCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE). Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.

Here you can find the meaning of Using a sequential implementation, it takes a total of 320 ns for each instruction, 300 ns for the combinational logic to complete, and 20 ns to store the result (in a register). This means that a throughput will be about 3.12 millions instructions/second. Assuming you switch to a 3 stage pipeline by splitting thecombinational logic into three equal parts and all registers take 20 ns to store resultsBy assuming the pipeline never starts, what will the improvement in throughput be?a)2 Instruction / 300 nsb)2 Instruction / 360 nsc)3 Instruction / 360 nsd)3 Instruction / 300 nsCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Using a sequential implementation, it takes a total of 320 ns for each instruction, 300 ns for the combinational logic to complete, and 20 ns to store the result (in a register). This means that a throughput will be about 3.12 millions instructions/second. Assuming you switch to a 3 stage pipeline by splitting thecombinational logic into three equal parts and all registers take 20 ns to store resultsBy assuming the pipeline never starts, what will the improvement in throughput be?a)2 Instruction / 300 nsb)2 Instruction / 360 nsc)3 Instruction / 360 nsd)3 Instruction / 300 nsCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Using a sequential implementation, it takes a total of 320 ns for each instruction, 300 ns for the combinational logic to complete, and 20 ns to store the result (in a register). This means that a throughput will be about 3.12 millions instructions/second. Assuming you switch to a 3 stage pipeline by splitting thecombinational logic into three equal parts and all registers take 20 ns to store resultsBy assuming the pipeline never starts, what will the improvement in throughput be?a)2 Instruction / 300 nsb)2 Instruction / 360 nsc)3 Instruction / 360 nsd)3 Instruction / 300 nsCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Using a sequential implementation, it takes a total of 320 ns for each instruction, 300 ns for the combinational logic to complete, and 20 ns to store the result (in a register). This means that a throughput will be about 3.12 millions instructions/second. Assuming you switch to a 3 stage pipeline by splitting thecombinational logic into three equal parts and all registers take 20 ns to store resultsBy assuming the pipeline never starts, what will the improvement in throughput be?a)2 Instruction / 300 nsb)2 Instruction / 360 nsc)3 Instruction / 360 nsd)3 Instruction / 300 nsCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Using a sequential implementation, it takes a total of 320 ns for each instruction, 300 ns for the combinational logic to complete, and 20 ns to store the result (in a register). This means that a throughput will be about 3.12 millions instructions/second. Assuming you switch to a 3 stage pipeline by splitting thecombinational logic into three equal parts and all registers take 20 ns to store resultsBy assuming the pipeline never starts, what will the improvement in throughput be?a)2 Instruction / 300 nsb)2 Instruction / 360 nsc)3 Instruction / 360 nsd)3 Instruction / 300 nsCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.