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Using a sequential implementation, it takes a total of 320 ns for each instruction, 300 ns for the combinational logic to complete, and 20 ns to store the result (in a register). This means that a throughput will be about 3.12 millions instructions/second. Assuming you switch to a 3 stage pipeline by splitting the combinational logic into three equal parts and all registers take 20 ns to store results
How long will it take for a single instruction to execute in the pipelined implementation?
  • a)
    300 ns
  • b)
    360 ns
  • c)
    100 ns
  • d)
    380 ns
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Using a sequential implementation, it takes a total of 320 ns for each...
Pipelined version will take
3 x 100 + 3 x 20 = 360 ns per instruction
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Using a sequential implementation, it takes a total of 320 ns for each instruction, 300 ns for the combinational logic to complete, and 20 ns to store the result (in a register). This means that a throughput will be about 3.12 millions instructions/second. Assuming you switch to a 3 stage pipeline by splitting thecombinational logic into three equal parts and all registers take 20 ns to store resultsHow long will it take for a single instruction to execute in the pipelined implementation?a)300 nsb)360 nsc)100 nsd)380 nsCorrect answer is option 'B'. Can you explain this answer?
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