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The content of TEMP location after the execution of the following program in a 8085 microprocessor is:
MVI B, 00H
MVI A, IC H
DCR B
DAA
STA TEMP
HLT
MVI B, 00H
MVI A, IC H
DCR B
DAA
STA TEMP
HLT
- a)10 H
- b)22 H
- c)1FH
- d)46 H
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The content of TEMP location after the execution of the following prog...
Decrement the content of B by one (initially B = 00 H)
B= FF H
D A A ; D A A instruction changes the binary values of contents of accumulator to BCD.
Since lower order nibble of A is more than 9 (i.e. C), AC flag is set and upper nibble is less than 9, therefore DAA adds 0110 H to lower order nibble of A to adjust binary result to Binary coded decimal.
Since lower order nibble of A is more than 9 (i.e. C), AC flag is set and upper nibble is less than 9, therefore DAA adds 0110 H to lower order nibble of A to adjust binary result to Binary coded decimal.
Most Upvoted Answer
The content of TEMP location after the execution of the following prog...
Program Execution:
1. MVI B, 00H: Move immediate value 00H into register B.
2. MVI A, IC: Move immediate value IC (in hexadecimal) into register A.
3. HDCR BD: Add the contents of register B and register D, and store the result in register D.
4. AA: Add the contents of register A with itself, and store the result in register A.
5. STA TEMP: Store the contents of register A into the memory location TEMP.
6. HLT: Halt the program.
Explanation:
- The program starts by moving the immediate value 00H into register B. This means that register B now contains 00H.
- Next, the immediate value IC is moved into register A. The value of IC is not provided in the question, so we cannot determine the exact value in register A.
- The instruction HDCR BD adds the contents of register B and register D and stores the result in register D. However, the contents of register D are not given in the program, so we cannot determine the exact value in register D.
- The instruction AA adds the contents of register A with itself and stores the result in register A. Again, since the value of register A is not provided, we cannot determine the exact value in register A.
- The instruction STA TEMP stores the contents of register A into the memory location TEMP. The exact value stored in TEMP depends on the value of register A, which is not given in the program.
- Finally, the program halts.
Content of TEMP:
Since the values of registers D and A are not provided, we cannot determine the exact value stored in TEMP. Therefore, we cannot determine the content of TEMP based on the given program. The correct answer cannot be determined from the information provided.
1. MVI B, 00H: Move immediate value 00H into register B.
2. MVI A, IC: Move immediate value IC (in hexadecimal) into register A.
3. HDCR BD: Add the contents of register B and register D, and store the result in register D.
4. AA: Add the contents of register A with itself, and store the result in register A.
5. STA TEMP: Store the contents of register A into the memory location TEMP.
6. HLT: Halt the program.
Explanation:
- The program starts by moving the immediate value 00H into register B. This means that register B now contains 00H.
- Next, the immediate value IC is moved into register A. The value of IC is not provided in the question, so we cannot determine the exact value in register A.
- The instruction HDCR BD adds the contents of register B and register D and stores the result in register D. However, the contents of register D are not given in the program, so we cannot determine the exact value in register D.
- The instruction AA adds the contents of register A with itself and stores the result in register A. Again, since the value of register A is not provided, we cannot determine the exact value in register A.
- The instruction STA TEMP stores the contents of register A into the memory location TEMP. The exact value stored in TEMP depends on the value of register A, which is not given in the program.
- Finally, the program halts.
Content of TEMP:
Since the values of registers D and A are not provided, we cannot determine the exact value stored in TEMP. Therefore, we cannot determine the content of TEMP based on the given program. The correct answer cannot be determined from the information provided.
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