Electronics and Communication Engineering (ECE) Exam > Electronics and Communication Engineering (ECE) Questions > The content of TEMP location after the execut...
Start Learning for Free
The content of TEMP location after the execution of the following program in a 8085 microprocessor is:
MVI B, 00H
MVI A, IC H
DCR B
DAA
STA TEMP
HLT
MVI B, 00H
MVI A, IC H
DCR B
DAA
STA TEMP
HLT
- a)10 H
- b)22 H
- c)1FH
- d)46 H
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
The content of TEMP location after the execution of the following prog...
Decrement the content of B by one (initially B = 00 H)
B= FF H
D A A ; D A A instruction changes the binary values of contents of accumulator to BCD.
Since lower order nibble of A is more than 9 (i.e. C), AC flag is set and upper nibble is less than 9, therefore DAA adds 0110 H to lower order nibble of A to adjust binary result to Binary coded decimal.
Since lower order nibble of A is more than 9 (i.e. C), AC flag is set and upper nibble is less than 9, therefore DAA adds 0110 H to lower order nibble of A to adjust binary result to Binary coded decimal.
Most Upvoted Answer
The content of TEMP location after the execution of the following prog...
Program Execution:
1. MVI B, 00H: Move immediate value 00H into register B.
2. MVI A, IC: Move immediate value IC (in hexadecimal) into register A.
3. HDCR BD: Add the contents of register B and register D, and store the result in register D.
4. AA: Add the contents of register A with itself, and store the result in register A.
5. STA TEMP: Store the contents of register A into the memory location TEMP.
6. HLT: Halt the program.
Explanation:
- The program starts by moving the immediate value 00H into register B. This means that register B now contains 00H.
- Next, the immediate value IC is moved into register A. The value of IC is not provided in the question, so we cannot determine the exact value in register A.
- The instruction HDCR BD adds the contents of register B and register D and stores the result in register D. However, the contents of register D are not given in the program, so we cannot determine the exact value in register D.
- The instruction AA adds the contents of register A with itself and stores the result in register A. Again, since the value of register A is not provided, we cannot determine the exact value in register A.
- The instruction STA TEMP stores the contents of register A into the memory location TEMP. The exact value stored in TEMP depends on the value of register A, which is not given in the program.
- Finally, the program halts.
Content of TEMP:
Since the values of registers D and A are not provided, we cannot determine the exact value stored in TEMP. Therefore, we cannot determine the content of TEMP based on the given program. The correct answer cannot be determined from the information provided.
1. MVI B, 00H: Move immediate value 00H into register B.
2. MVI A, IC: Move immediate value IC (in hexadecimal) into register A.
3. HDCR BD: Add the contents of register B and register D, and store the result in register D.
4. AA: Add the contents of register A with itself, and store the result in register A.
5. STA TEMP: Store the contents of register A into the memory location TEMP.
6. HLT: Halt the program.
Explanation:
- The program starts by moving the immediate value 00H into register B. This means that register B now contains 00H.
- Next, the immediate value IC is moved into register A. The value of IC is not provided in the question, so we cannot determine the exact value in register A.
- The instruction HDCR BD adds the contents of register B and register D and stores the result in register D. However, the contents of register D are not given in the program, so we cannot determine the exact value in register D.
- The instruction AA adds the contents of register A with itself and stores the result in register A. Again, since the value of register A is not provided, we cannot determine the exact value in register A.
- The instruction STA TEMP stores the contents of register A into the memory location TEMP. The exact value stored in TEMP depends on the value of register A, which is not given in the program.
- Finally, the program halts.
Content of TEMP:
Since the values of registers D and A are not provided, we cannot determine the exact value stored in TEMP. Therefore, we cannot determine the content of TEMP based on the given program. The correct answer cannot be determined from the information provided.
Attention Electronics and Communication Engineering (ECE) Students!
To make sure you are not studying endlessly, EduRev has designed Electronics and Communication Engineering (ECE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electronics and Communication Engineering (ECE).
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Top Courses for Electronics and Communication Engineering (ECE)View all
The content of TEMP location after the execution of the following program in a 8085 microprocessor is:MVI B, 00HMVI A, IC HDCR BDAASTA TEMPHLTa)10 Hb)22 Hc)1FHd)46 HCorrect answer is option 'B'. Can you explain this answer?
Question Description
The content of TEMP location after the execution of the following program in a 8085 microprocessor is:MVI B, 00HMVI A, IC HDCR BDAASTA TEMPHLTa)10 Hb)22 Hc)1FHd)46 HCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The content of TEMP location after the execution of the following program in a 8085 microprocessor is:MVI B, 00HMVI A, IC HDCR BDAASTA TEMPHLTa)10 Hb)22 Hc)1FHd)46 HCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The content of TEMP location after the execution of the following program in a 8085 microprocessor is:MVI B, 00HMVI A, IC HDCR BDAASTA TEMPHLTa)10 Hb)22 Hc)1FHd)46 HCorrect answer is option 'B'. Can you explain this answer?.
The content of TEMP location after the execution of the following program in a 8085 microprocessor is:MVI B, 00HMVI A, IC HDCR BDAASTA TEMPHLTa)10 Hb)22 Hc)1FHd)46 HCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The content of TEMP location after the execution of the following program in a 8085 microprocessor is:MVI B, 00HMVI A, IC HDCR BDAASTA TEMPHLTa)10 Hb)22 Hc)1FHd)46 HCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The content of TEMP location after the execution of the following program in a 8085 microprocessor is:MVI B, 00HMVI A, IC HDCR BDAASTA TEMPHLTa)10 Hb)22 Hc)1FHd)46 HCorrect answer is option 'B'. Can you explain this answer?.
Solutions for The content of TEMP location after the execution of the following program in a 8085 microprocessor is:MVI B, 00HMVI A, IC HDCR BDAASTA TEMPHLTa)10 Hb)22 Hc)1FHd)46 HCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE).
Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.
Here you can find the meaning of The content of TEMP location after the execution of the following program in a 8085 microprocessor is:MVI B, 00HMVI A, IC HDCR BDAASTA TEMPHLTa)10 Hb)22 Hc)1FHd)46 HCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The content of TEMP location after the execution of the following program in a 8085 microprocessor is:MVI B, 00HMVI A, IC HDCR BDAASTA TEMPHLTa)10 Hb)22 Hc)1FHd)46 HCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The content of TEMP location after the execution of the following program in a 8085 microprocessor is:MVI B, 00HMVI A, IC HDCR BDAASTA TEMPHLTa)10 Hb)22 Hc)1FHd)46 HCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The content of TEMP location after the execution of the following program in a 8085 microprocessor is:MVI B, 00HMVI A, IC HDCR BDAASTA TEMPHLTa)10 Hb)22 Hc)1FHd)46 HCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The content of TEMP location after the execution of the following program in a 8085 microprocessor is:MVI B, 00HMVI A, IC HDCR BDAASTA TEMPHLTa)10 Hb)22 Hc)1FHd)46 HCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
|
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
x
![]()
For Your Perfect Score in Electronics and Communication Engineering (ECE)
The Best you need at One Place
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup